I want to clip a bunch of images into hexagon shapes. I have it sort of working, but the clipping is across all the hexes instead of each image clipping to only one hex. What am I doing wrong?
Here's a live demo: http://codepen.io/tev/pen/iJaHB
Here's the js in question:
function polygon(ctx, x, y, radius, sides, startAngle, anticlockwise, img, imgX, imgY) {
if (sides < 3) return;
var a = (Math.PI * 2)/sides;
a = anticlockwise?-a:a;
ctx.save();
ctx.translate(x,y);
ctx.rotate(startAngle);
ctx.moveTo(radius,0);
for (var i = 1; i < sides; i++) {
ctx.lineTo(radius*Math.cos(a*i),radius*Math.sin(a*i));
}
ctx.closePath();
// add stroke
ctx.lineWidth = 5;
ctx.strokeStyle = '#056e96';
ctx.stroke();
// add stroke
ctx.lineWidth = 4;
ctx.strokeStyle = '#47b6c8';
ctx.stroke();
// add stroke
ctx.lineWidth = 2;
ctx.strokeStyle = '#056e96';
ctx.stroke();
// Clip to the current path
ctx.clip();
ctx.drawImage(img, imgX, imgY);
ctx.restore();
}
// Grab the Canvas and Drawing Context
var canvas = document.getElementById('c');
var ctx = canvas.getContext('2d');
// Create an image element
var img = document.createElement('IMG');
var img2 = document.createElement('IMG');
// When the image is loaded, draw it
img.onload = function () {
polygon(ctx, 120,120,100,6, 0,0,img, -120,-170);
}
img2.onload = function () {
polygon(ctx, 280,212,100,6, 0,0,img2, -150,-120);
}
// Specify the src to load the image
img.src = "http://farm8.staticflickr.com/7381/9601443923_051d985646_n.jpg";
img2.src = "http://farm6.staticflickr.com/5496/9585303170_d005d2aaa9_n.jpg";
You need to add this to your polygon()
method:
ctx.beginPath();
function polygon(ctx, x, y, radius, sides, startAngle, anticlockwise, img, ...
if (sides < 3) return;
var a = (Math.PI * 2)/sides;
a = anticlockwise?-a:a;
ctx.save();
ctx.translate(x,y);
ctx.rotate(startAngle);
ctx.beginPath(); /// for example here, before moveTo/lineTo
ctx.moveTo(radius,0);
...
If not the lines will accumulate so the second time you call polygon the previous polygon will still exist. That's why you see the image partly inside the first hexagon as well.
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