Variables from included php file
Question
I currently have a php file with html code in it. At the beginning of the body tag im including a dbcon.php which contains a db connection, a query and a fetch_result. I now want to use those results later in the html file but i cant get it to work.
Website-file looks like this:
<html>
<head>...</head>
<body>
<?php include("dbcon.php"); ?>
...
<some html stuff>
...
<? here i want to use the data from the query ?>
...
</body></html>
The dbcon.php simply contains the connection, the query and the fetch_results.
edit: dbcon:
<?php
$con=mysql_connect("localhost:8889","user","pw","db");
$result_query = mysql_query($con,"SELECT * FROM table");
$results = mysql_fetch_array($results_query);
?>
I cant access the data in the lower part of the html file.
2 answers
solution1
0 ACCPTED 2013-11-26 10:56:19
Your code is "right", in that you don't need anything more to access your dbcon.php variables.
But you're mixing mysql_ and mysqli_ syntax :
-
mysql_querytake as first parameter the query, not the connexion -
mysqli_querytake as first parameter the connexion, and the query as second one
You should use mysqli_ :
$con = mysqli_connect("localhost:8889","user","pw","db");
$result_query = mysqli_query($con, "SELECT * FROM table");
$results = mysqli_fetch_array($results_query);
Another version, object oriented :
$mysqli = new mysqli("localhost:8889", "user", "pw", "db");
if ($mysqli->connect_errno) {
printf("Connect failed: %s\n", $mysqli->connect_error);
exit();
}
$results = array();
if ($result_query = $mysqli->query("SELECT * FROM table")) {
$results = $result_query->fetch_array();
}
solution2
0 2013-11-26 11:02:36
don't use mysql_ function,it is depricated.
anyway you use wrong variable name. $results_query in mysql_fetch_array($results_query) so change it to $result_query and it might work.
<?php
$con=mysql_connect("localhost:8889","user","pw","db");
$result_query = mysql_query("SELECT * FROM table");
$results = mysql_fetch_array($result_query );
?>
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