How to select value of all the tbody inputs values using jQuery

Question

so I have some checkboxes, when each one is checked I'm able to get the id number I need from the associated table row and place them into my contacts array.

I also have a Select all checkbox which is meant to grab all the id numbers and stick them into the same array.

Having a bit of trouble trying to figure out the correct syntax to target the tbody, select every table row's data-id, or every table row's input's value.

http://jsfiddle.net/leongaban/7LCjH/

^ In my fiddle example you can see the numbers get added to my array (or the gray div for visualization).

---

How would you grab all the id numbers from the tbody rows from the Select all checkbox?

jQuery

<table>

<thead>
    <tr>
        <td><input type="checkbox" id="selectall"/></td>
        <td>Select All</td>
    </tr>
    <tr>
        <td colspan="2"><hr/></td>
    </tr>
</thead>

<tbody id="tbody">
    <tr data-coworker-id="1">
        <td><input type="checkbox" class="case" name="case" value="1"/></td>
        <td>1</td>
    </tr>
    <tr data-coworker-id="2">
        <td><input type="checkbox" class="case" name="case" value="2"/></td>
        <td>2</td>
    </tr>
    <tr data-coworker-id="3">
        <td><input type="checkbox" class="case" name="case" value="3"/></td>
        <td>3</td>
    </tr>
</tbody>

HTML

 <table> <thead> <tr> <td><input type="checkbox" id="selectall"/></td> <td>Select All</td> </tr> <tr> <td colspan="2"><hr/></td> </tr> </thead> <tbody id="tbody"> <tr data-coworker-id="1"> <td><input type="checkbox" class="case" name="case" value="1"/></td> <td>1</td> </tr> <tr data-coworker-id="2"> <td><input type="checkbox" class="case" name="case" value="2"/></td> <td>2</td> </tr> <tr data-coworker-id="3"> <td><input type="checkbox" class="case" name="case" value="3"/></td> <td>3</td> </tr> </tbody> 

Answer 1

You can modify your select all handler like so:

$("#selectall").click(function () {
    $('.case').attr('checked', this.checked).each(function() {
         contacts.push($(this).val())
    });
});

Answer 2

Here is a working example:

var contacts = [];

// add multiple select / deselect functionality

$("#selectall").click(function () {
    var els = $('.case')
    if (els.first().is(':checked') ) {
        els.prop('checked', false);
        $('#arrayContent').empty();
    } else {
        els.attr('checked', true);
        $.each(els, function(index, el) {
             contacts.push( $(el).val() ); 
        });
        $('#arrayContent').empty();
        $('#arrayContent').append(contacts.join( ', ' ) );
    }
    //contacts.push($('#tbody').children(tr > td > input).val();)
});

// if all checkbox are selected, check the selectall checkbox
// and viceversa

$(".case").click(function() {

    var $tr = $(this).closest("tr");
    var id = $tr.data('coworker-id');

    contacts.push(id);

    $('#arrayContent').empty();
    $('#arrayContent').append(contacts+',');

    if ($(".case").length == $(".case:checked").length) {
        $("#selectall").attr("checked", "checked");
    } else {
        $("#selectall").removeAttr("checked");
    }   

});

and here is fiddle link :: http://jsfiddle.net/kkemple/7LCjH/24/

Answer 3

You can try this

$("#selectall").click(function () {

if($('.case:checked').length == $('.case').length){
    //deselect all
    $('.case').removeAttr("checked");
    contacts = [];
}
else{
    //select all
    $('.case').attr("checked", "checked").each(function(){

        var $tr = $(this).closest("tr");
        var id = $tr.data('coworker-id');

        contacts.push(id);

    })
}    




$('#arrayContent').empty();
$('#arrayContent').append(contacts.join(','));
//contacts.push($('#tbody').children(tr > td > input).val();)
});

jsFiddle

Answer 4

Use find instead of children and then loop the elements to add them to the array.

$("#selectall").click(function () {
  $('.case').attr('checked', this.checked);
  $('tbody').find("input").each(function () {
    contacts.push($(this).val()+",");
  });
  $('#arrayContent').append(contacts);
});

The .find() and .children() methods are similar, except that the latter only travels a single level down the DOM tree.

Source: http://api.jquery.com/find/

Answer 5

我知道这不能完全解决使用子项的问题，但是您可以使用$('#tbody').find('input')查找元素中的所有输入字段。