<script type="text/javascript">
var timeOutID = 0;
var checkScores = function() {
$.ajax({
url: "<?php echo 'http://127.0.0.1/ProgVsProg/main/countScoreCh'?>",
success:function(response){
if (response !=' ') {
$('#scoreCh').html(response);
clearTimeout(timeOutID);
} else{
timeOutID = setTimeout(checkScores, 3000);
}
});
}
timeOutID = setTimeout(checkScores,1000);
</script>
I am using setTimeout
if there is a change in the database. If there is a change..it will output the change.
My problem is setTimeout
will only display the first call.and never checks again if there is another change in the database.
I don't know if setTimeout
is the correct way of doing it.
Yeah, setTimeout only runs once though. You're looking for setInterval.
<script type="text/javascript">
var timeOutID = 0;
var checkScores = function() {
$.ajax({
url: "<?php echo 'http://127.0.0.1/ProgVsProg/main/countScoreCh'?>",
success: function(response) {
if(response !== '') {
$('#scoreCh').html(response);
}
}
});
};
timeOutID = setInterval(checkScores, 1000);
</script>
You could also get it working by just getting rid of that else in your success function:
success: function(response) {
if(response !== '') {
$('#scoreCh').html(response);
}
timeOutID = setTimeout(checkScores, 3000);
},
error: function() {
timeOutID = setTimeout(checkScores, 3000);
}
You are making these mistakes
setTimeout
. Instead use setInterval
and clear this interval depending upon your logic like after 50times or something else. asynchronous
call. (As suggested by @mike) Try this
var intervalId = null;
var IS_BUSY_FETCHING_UPDATES = false;
var checkScores = function() {
if (!IS_BUSY_FETCHING_UPDTAES) {
IS_BUSY_FETCHING_UPDTAES = true;
$.ajax({
url: "http://127.0.0.1/ProgVsProg/main/countScoreCh"
}).done(function(response){
if (response) {
$('#scoreCh').html(response);
}
}).fail(function(e) {
console.error(e);
}).always(function() {
IS_BUSY_FETCHING_UPDATES = false; // This will be executed when AJAX gets complete
});
}
intervalID = setInterval(checkScores,1000);
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