python 3 http socket not working
Question
My code:
import socket
host = ''
port = 8090
backlog = 5
size = 1024
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.bind((host,port))
s.listen(backlog)
while 1:
client, address = s.accept()
#data = client.recv(size)
data= "ok"
if data:
client.send(bytes('HTTP/1.0 200 OK<CRLF>', 'UTF-8'))
client.send(bytes("Content-Type: text/html<CRLF><CRLF>", 'UTF-8'))
client.send(bytes('<html><body><h1>Hello World</body></html>', 'UTF-8'))
client.close()
for some reason whenever i visit: http:localhost:8090 google chrome returns:
"The webpage at http:localhost:8090 might be temporarily down or it may have moved permanently to a new web address."
I looked up tons of examples, and I have no clue why this is not working
I am running python 3.3 on windows 7, thankyou.
1 answers
solution1
0 ACCPTED 2014-01-10 03:14:13
Your <CRLF> characters should be \\r\\n in python. If you then put the .recv back in it works:
import socket
host = ''
port = 8090
backlog = 5
size = 1024
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.bind((host,port))
s.listen(backlog)
while 1:
client, address = s.accept()
data = client.recv(size)
if data:
client.send(bytes('HTTP/1.0 200 OK\r\n', 'UTF-8'))
client.send(bytes("Content-Type: text/html\r\n\r\n", 'UTF-8'))
client.send(bytes('<html><body><h1>Hello World</body></html>', 'UTF-8'))
client.close()
Python uses the backslash \\ character for escaping in strings. See http://docs.python.org/2/reference/lexical_analysis.html#strings for more details.
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