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CakePhp html link query

我希望在另一个浏览器选项卡中打开一个链接,而不是用户所在的位置。

<?=__('Development by ').$this->Html->link('Test','http://www.test.cl',array('class'=>'orange-link'));?> 

First, don't use php short tags, they simply suck and can cause issues.

Learn some HTML basics: http://www.w3schools.com/tags/att_a_target.asp

The target attribute specifies where to open the linked document.

$this->Html->link('Lixsys','http://www.lixsys.cl',array(
    'class'=> 'orange-link'
    'target'=> '_blank'
));

You must use the target _blank that opens a new blank tab you want to open the link and the link arm use $this->Html->link

http://book.cakephp.org/2.0/en/core-libraries/helpers/html.html

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