ODD and EVEN Digits

Question

i have a code capturing ODD EVEN numbers in a textbox , is there a betterway of doing this in minimal code? or maybe much faster performance? thnks -john :)

                string givenamnt = Convert.ToString(txtamount.Amount.Replace(".", ""));
                int glength = givenamnt.Length;
                var regex = new Regex("[1]|[3]|[5]|[7]|[9]");

                string odd = null;
                string even = null;

                for (int i = 0; i < glength; i++)
                {
                var x1 = givenamnt.Substring(i, 1);
                var isOdd = regex.IsMatch(x1);

                if (isOdd)
                {
                odd += x1;
                txtodd1.Text = odd;
                }
                else
                {
                even += x1;
                txteven1.Text = even;
                }
                }

Answer 1

Yes.You can use Modulus

if( Convert.ToInt32(x1) % 2 == 0 ) //even
else // odd

Answer 2

Definitely not an elegant solution, but to get the actual even and odd digits you can use this:

    string str = "230sd85"; // sample string with invalid input for numbers
    var odd = str
            .Where(x => char.IsDigit(x)  
                && Convert.ToInt32(x) % 2 != 0);

    var even = str
             .Where(x => char.IsDigit(x) 
                && Convert.ToInt32(x) % 2 == 0);

    string oddNums = string.Join("", odd); // 35 - the numbers 3 and 5, not 35
    string evenNums = string.Join("", even); // 208 - the numbers 2, 0 and 8

Is this what you meant by digits?