{{ render(controller("SomeBundle:Foo:Bar", {HERE I WANT TO PASS ALL query parameters app.request.query.all}) }}
那么我可以在子请求中访问所有主请求查询参数吗?子请求也应该独立运行?
Try this:
{{ render(controller("SomeBundle:Foo:bar", {'all': app.request.query.all}) }}
and in action store it in $all
variable
public function barAction($all) {
// other your code
}
From your controller:
array_merge($request->query->all(), $request->get('_route_params'));
//query->all : get all query string parameters
//_route_params : get current route parameters
From your twig template must be sth like:
app.request.query.all|merge(app.request.attributes.get('_route_params'))
I've never used this in twig templates, so first test it ;)
Then you can use that functions however you want to build the variables you'll pass to your subrequest
To just pass in what is in app.request.query.all:
{{ render(controller("SomeBundle:Foo:Bar", app.request.query.all)
To merge something extra in:
{{ render(controller("SomeBundle:Foo:Bar", { something: 'extra' }|merge(app.request.query.all))
Tested in Symfony 3.3.10 and Twig 1.35.0
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