I have this very simple xml file :
<?xml version="1.0" encoding="UTF-8"?>
<ConfigurationFile>
<ConfigurationFilePath>Test1</ConfigurationFilePath>
<ConnectionString>Test2</ConnectionString>
<AnalyzeFilePath>Test3</AnalyzeFilePath>
</ConfigurationFile>
And I want to get informations of each field. But this doesn't display anything..
Here is my C# code behind :
private void ParseXMLFile()
{
Console.WriteLine("Parse");
if (configurationPAthFileTextbox.Text != null)
{
Console.WriteLine("file != null");
try
{
XElement main = XElement.Load(configurationPAthFileTextbox.Text);
var results = main.Descendants("ConfigurationFile")
.Select(e => new { ConfigurationFilePath = e.Descendants("ConfigurationFilePath").FirstOrDefault().Value,
ConnectionString = e.Descendants("ConnectionString").FirstOrDefault().Value });
foreach (var result in results)
Console.WriteLine("{0}, {1}", result.ConfigurationFilePath, result.ConnectionString);
Console.ReadLine();
}
catch (Exception e)
{
Debug.WriteLine(e.ToString());
}
}
}
Load it as XDocument
, because it's a document, not an element.
var xDoc = XDocument.Load(configurationPAthFileTextbox.Text);
You can easily convert your document into Dictionary<string, string>
with element names as keys and element values as values:
var results = xDoc.Root .Elements() .ToDictionary(e => e.Name, e => (string)e);
To print ConfigurationFilePath
and ConnectionString
:
Console.WriteLine("{0}, {1}", results["ConfigurationFilePath"], results["ConnectionString"]);
Prints Test1, Test2
.
First, create a class to represent the information of interest contained in your XML file. Define a constructor that extracts the values of interest from your XML file and maps them to the properties of your class:
public class ConfigurationFile
{
public String ConfigurationFilePath { get; set; }
public String ConnectionString { get; set; }
public String AnalyzeFilePath { get; set; }
public ConfigurationFile(String xmlFilePath)
{
XDocument document = XDocument.Load(xmlFilePath);
var root = document.Root;
ConfigurationFilePath = (string)root.Element("ConfigurationFilePath");
ConnectionString = (string)root.Element("ConnectionString");
AnalyzeFilePath = (string)root.Element("AnalyzeFilePath");
}
}
Once you have created this class with its special constructor, making use of the class is very straightforward:
var configFile = new ConfigurationFile(xmlFilePath);
var path = configFile.ConfigurationFilePath;
var connectString = configFile.ConnectionString;
var analyzeFilePath = configFile.AnalyzeFilePath;
Here's a demonstration program that puts it all together. (Please note that in this demo program the constructor loads the XML from a string rather than from a file as shown above.)
using System;
using System.Xml;
using System.Xml.Linq;
class LinqToXmlDemo
{
static public void Main(string[] args)
{
string xmlContent = GetXml();
var configFile = new ConfigurationFile(xmlContent);
Console.WriteLine
("ConfigurationFilePath:[{0}]\n" +
"ConnectionString:[{1}]\n" +
"AnalyzeFilePath:[{2}]\n--",
configFile.ConfigurationFilePath,
configFile.ConnectionString,
configFile.AnalyzeFilePath);
}
static string GetXml()
{
return
@"<?xml version='1.0' encoding='UTF-8'?>
<ConfigurationFile>
<ConfigurationFilePath>Test1</ConfigurationFilePath>
<ConnectionString>Test2</ConnectionString>
<AnalyzeFilePath>Test3</AnalyzeFilePath>
</ConfigurationFile>";
}
}
public class ConfigurationFile
{
public String ConfigurationFilePath { get; set; }
public String ConnectionString { get; set; }
public String AnalyzeFilePath { get; set; }
public ConfigurationFile(String xml)
{
XDocument document = XDocument.Parse(xml);
var root = document.Root;
ConfigurationFilePath = (string)root.Element("ConfigurationFilePath");
ConnectionString = (string)root.Element("ConnectionString");
AnalyzeFilePath = (string)root.Element("AnalyzeFilePath");
}
}
Expected Output
ConfigurationFilePath:[Test1]
ConnectionString:[Test2]
AnalyzeFilePath:[Test3]
--
Simply, You can use too:
string yourString = (string)(from element in xDocument.Root.Descendants("ConfigurationFilePath") select element).First();
=D
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