How to pass parameters in nginx url. When I hit http://127.0.0.1:1000/samp/test1/result?num1=10&num2=30
, it should redirect me to http://127.0.0.1:80/samp/test1/result?num1=10&num2=30
. Is this possible? Below is my nginx config file.
upstream apache {
server 127.0.0.1:1000;
}
server {
listen 80;
server_name 127.0.0.1;
location / {
#root html;
#index index.html index.htm;
#return 503;
proxy_pass http://apache;
}
}
I think what you want to do is possibe, but you'd have to make that configuration change on the apache end of things.
If 'apache' handles a request coming into port 1000 directly, it will see a URI like this:
http://127.0.0.1:1000/samp/test1/result?num1=10&num2=30
However, if it is sent through nginx, it will look more like this:
http://apache/samp/test1/result?num1=10&num2=30
So, you could check the incoming URL for :1000 and then rewrite the request on the apache side to go to port 80 instead ( which is the default, so you don't need :80
- you can just leave the port unspecified entirely.
If the backend really is apache, you can use a rewrite rule there to handle the rewriting.
However, if you're not already on port 80, you're not connecting to nginx - so nginx can't rewrite this for you.
Hope it makes sense!
Here's how I tested:
Apache side I used a quick sinatra (ruby) app to print out the full URI of the request it sees:
require 'sinatra'
set :bind, "0.0.0.0"
set :port, 1025
get "/*" do
"<p>Hello from \"apache\"! You've just requested:
<code>#{request.url}</code></p>
"
end
Then nginx is configured thusly:
upstream apache {
server 192.168.70.1:1025;
}
server {
server_name localhost;
location / {
proxy_pass http://apache;
}
}
Note I used port 1025, because port 1000 is a privileged port.
I used curl to generate the requests to test:
$ curl 'http://192.168.70.1:1025/samp/test1/result?num1=10&num2=30'
<p>Hello from "apache"! You've just requested:
<code>http://192.168.70.1:1025/samp/test1/result?num1=10&num2=30</code></p>
$curl 'http://127.0.0.1:80/samp/test1/result?num1=10&num2=30'
<p>Hello from "apache"! You've just requested:
<code>http://apache/samp/test1/result?num1=10&num2=30</code></p>
If I wanted to do the redirect you're describing, I could match with a regular expression of IPV4 address and port and redirect as such:
get "/*" do
if request.url =~ %r|^http://([0-9]{1,3}\.){3}[0-9]{1,3}:1025/|
redirect "http://localhost:80/#{request.fullpath}"
else
"<p>Hello from \"apache\"! Tou've just requested:
<code>#{request.url}</code></p>
"
end
end
Now I tell curl
to follow redirects (-L) and we see it redirect me over to the "correct" route.
$ curl -L 'http://192.168.70.1:1025/samp/test1/result?num1=10&num2=30'
<p>Hello from "apache"! Tou've just requested:
<code>http://apache/samp/test1/result?num1=10&num2=30</code></p>
I know it's not the language you're using, but I hope it iwll help you get started.
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