I have made sure the id in table1 is primary and auto-incrementing. Even the insert is happening successfully. However, in table2 id is 0. Also, mysqli_real_escape_string is not working with $_POST['xyz1'] in this case.
<?php
include ('db.php');
session_start();
$q1="insert into xyz (email, content) values ('".$_SESSION['Email']."','".$_POST['xyz1']."')";
$query1=mysqli_query($pqr,$q1);
$a=mysqli_insert_id();
$q2="insert into xyz2 (email,content2,id) values ('".$_SESSION['Email']."','".$_POST['xyz3']."', '".$a."')";
$query2=mysqli_query($pqr,$q2);
echo "done";
?>
You obviously need the mysqli_insert_id()
function of mysqli, you missed the i
.
Also: Switch to Prepared Statements, instead of using mysqli_real_escape_string
. They are far superior.
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