Passing variable trought url
Question
I'm having a problem I have no idea what's going on, probablly is just a silly thing but I need you help.
If got a very simple login file(starting) is this one:
<?php
include("conex.phtml");
$link=Conectarse();
$username = $_POST['username'];
$pass = $_POST['pass'];
$city = "";
$latitude = "";
$longitude = "";
//$obj = array();
$empty="empty";
$rows0="rows0";
$id="";
$result=mysql_query("select * from user where username='" . $username . "' and password=" . $pass, $link);
if(!$result){
header('Location: http://www.ihaveseen.org/index.html');
}else{
if($rs = mysql_fetch_array($result)){
if ($rs==''){
header('Location: http://www.ihaveseen.org/index.html');
} else {
$id = $rs['id'];
echo'<script>window.location="http://www.ihaveseen.org/main.php?id=hola";</script>';
/*header('Location: http://www.ihaveseen.org/main.php?id=hola');*/
//echo '' . $rs['id'] . '';
//header('Location: check_incoming.php?id=' . $id);
}
}else{
header('Location: http://www.ihaveseen.org/index.html');
}
}
mysql_close($link);
exit();
?>
I'm trying to pass via url a variable called id = hola, very simple, right? When I go to the next file, "main.php" the code sends me a syntax error in the javascript script.
<?php
$id = $_GET['id'];
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<html>
<head>
<meta http-equiv="content-type" content="text/html; charset=UTF-8">
<title>Woyou</title>
</head>
<link rel="stylesheet" href="./styles/styles16.css" type="text/css" id="css"/>
<script type="text/javascript" charset="UTF-8">
var id = getUrlVars()["id"];
alert("hola");
</script>
<body onload="" onunload="GUnload();" onkeydown="" onkeyup="" id="body">
<div id="guarda" style="display: none;"></div>
<iframe src='woyou.html' id="woyou_frame" name="woyou_frame" frameborder="0" scrolling="no"></iframe>
</body>
</html>
What am I doing wrong?
4 answers
solution1
1 2014-03-24 11:16:50
You can directly get the value:
<script type="text/javascript" charset="UTF-8">
var id = '<?php echo $id ?>';
alert("hola");
</script>
solution2
0 ACCPTED 2014-03-24 11:18:29
Re-write the html to look like this:
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="content-type" content="text/html; charset=UTF-8">
<title>Woyou</title>
<link rel="stylesheet" href="./styles/styles16.css" type="text/css" id="css"/>
<script type="text/javascript" charset="UTF-8">
var id = getUrlVars()["id"];
alert("hola");
</script>
</head>
<body onload="" onunload="GUnload();" onkeydown="" onkeyup="" id="body">
<div id="guarda" style="display: none;"></div>
<iframe src='woyou.html' id="woyou_frame" name="woyou_frame" frameborder="0" scrolling="no"></iframe>
</body>
</html>
You had two opening html tags and the script and link tags were not in the head tag like it's supposed to be.
solution3
0 2014-03-24 11:20:17
getUrlVars is not defined in your page. Just paste this into your script tag (at the top)
function getUrlVars() {
var vars = {};
var parts = window.location.href.replace(/[?&]+([^=&]+)=([^&]*)/gi, function(m,key,value) {
vars[key] = value;
});
return vars;
}
solution4
0 2014-03-24 11:43:03
Consider correcting the query from
$result= mysql_query("select * from user where username='" . $username . "'
and password=" . $pass, $link);
to
$result= mysql_query("select * from user where username='" . $username . "'
and password='" . $pass."'", $link);
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.