简体   繁体   中英

Mouse Position Python Tkinter

有没有办法获得鼠标的位置并将其设置为var?

At any point in time you can use the method winfo_pointerx and winfo_pointery to get the x,y coordinates relative to the root window. To convert that to absolute screen coordinates you can get the winfo_pointerx or winfo_pointery , and from that subtract the respective winfo_rootx or winfo_rooty

For example:

root = tk.Tk()
...
x = root.winfo_pointerx()
y = root.winfo_pointery()
abs_coord_x = root.winfo_pointerx() - root.winfo_rootx()
abs_coord_y = root.winfo_pointery() - root.winfo_rooty()

You could set up a callback to react to <Motion> events:

import Tkinter as tk
root = tk.Tk()

def motion(event):
    x, y = event.x, event.y
    print('{}, {}'.format(x, y))

root.bind('<Motion>', motion)
root.mainloop()

I'm not sure what kind of variable you want. Above, I set local variables x and y to the mouse coordinates.

If you make motion a class method, then you could set instance attributes self.x and self.y to the mouse coordinates, which could then be accessible from other class methods.

Personally, I prefer to use pyautogui , even in combination with Tkinter. It is not limited to Tkinter app, but works on the whole screen, even on dual screen configuration.

    import pyautogui
    x, y = pyautogui.position()

In case you want to save various positions, add an on-click event.
I know original question is about Tkinter.

I would like to improve Bryan's answer, as that only works if you have 1 monitor, but if you have multiple monitors, it will always use your coordinates relative to your main monitor. in order to find it relative to both monitors, and get the accurate position, then use vroot , instead of root , like this

root = tk.Tk()
...
x = root.winfo_pointerx()
y = root.winfo_pointery()
abs_coord_x = root.winfo_pointerx() - root.winfo_vrootx()
abs_coord_y = root.winfo_pointery() - root.winfo_vrooty()

The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM