How to make PHP code check if inserted current password is correct password from MySQL database

Question

I am making website settings form, where user could change password and email address.

My code is following:

<meta charset="UTF-8"/>
<?php
include_once 'init/init.funcs.php';

$kehtiv_parool=mysql_real_escape_string($_POST['kehtiv_parool']);
$kehtiv_parool_uuesti=mysql_real_escape_string($_POST['kehtiv_parool_uuesti']);
$uus_parool=mysql_real_escape_string($_POST['uus_parool']);
$kinnita_uus_parool=mysql_real_escape_string($_POST['kinnita_uus_parool']);
$email=mysql_real_escape_string($_POST['email']);
$userid=$_SESSION['user'];
$current_password = mysql_query("SELECT parool FROM kasutajad WHERE kasutaja_id ='$userid'");


if ($kehtiv_parool==$kehtiv_parool_uuesti){
    if ($kehtiv_parool==$current_password){
        if ($uus_parool==$kinnita_uus_parool){
            mysql_query ("UPDATE kasutajad SET parool='$uus_parool' WHERE kasutaja_id='$userid'");
            echo "parool muudetud";
            }

        if (!empty($_POST['email'])){
            mysql_query ("UPDATE kasutajad SET e_mail='$email' WHERE kasutaja_id='$userid' ");
            echo "e-mail muudetud";
    }
    }
    else
        echo "Sisestatud kehtiv parool ei ole korrektne";

}
else
    echo "Sisestatud kehtivad paroolid ei kattu";

?>

When I remove some code it works:

<meta charset="UTF-8"/>
<?php
include_once 'init/init.funcs.php';

$kehtiv_parool=mysql_real_escape_string($_POST['kehtiv_parool']);
$kehtiv_parool_uuesti=mysql_real_escape_string($_POST['kehtiv_parool_uuesti']);
$uus_parool=mysql_real_escape_string($_POST['uus_parool']);
$kinnita_uus_parool=mysql_real_escape_string($_POST['kinnita_uus_parool']);
$email=mysql_real_escape_string($_POST['email']);
$userid=$_SESSION['user'];
$current_password = mysql_query("SELECT parool FROM kasutajad WHERE kasutaja_id ='$userid'");


if ($kehtiv_parool==$kehtiv_parool_uuesti){
        if ($uus_parool==$kinnita_uus_parool){
            mysql_query ("UPDATE kasutajad SET parool='$uus_parool' WHERE kasutaja_id='$userid'");
            echo "parool muudetud";


        if (!empty($_POST['email'])){
            mysql_query ("UPDATE kasutajad SET e_mail='$email' WHERE kasutaja_id='$userid' ");
            echo "e-mail muudetud";
    }
    }
    else
        echo "Sisestatud kehtiv parool ei ole korrektne";

}
else
    echo "Sisestatud kehtivad paroolid ei kattu";

But now it wont check if inserted old password is correct password of user, how should I write this code to make it work? Variable kehtiv_parool holds value of current password which user inserted in html form and kehtiv_parool_uuesti is confirmation of same thing.

My HTML is following:

<html>
<head>
<meta charset="UTF-8"/>
<title>Seaded</title>
</head>
<body>
<p>Täida väljad, mida soovid muuta</p>
<form action="seaded.php" method="POST">
<br>Uus parool<input type="password" name="uus_parool"> <br>

<br>Kinnita uus parool <input type="password" name="kinnita_uus_parool">
<br>

<br>e-mail             <input type="text" name="email"><br>
<hr>
<br>Sisesta kehtiv parool <input type="password" name="kehtiv_parool"><br>

<br>Sisesta kehtiv parool uuesti <input type="password" name="kehtiv_parool_uuesti"><br>


<input type="submit" value="Kinnita">

</form>



</body>
</html>

Answer 1

您可以在登录到数据库的会话中添加加密的pw，然后在每一页上检查加密的pw，然后等到该页面继续操作，否则清除会话并重定向到索引页（例如登录名）页）

Answer 2

You need to call mysql_fetch_assoc to get the row that the query returns.

$current_password_result = mysql_query("SELECT parool FROM kasutajad WHERE kasutaja_id ='$userid'");
$current_password_row = mysql_fetch_assoc($current_password_result);
$current_password = $current_password_row ? $current_password_row['parool'] : null;

if ($kehtiv_parool==$kehtiv_parool_uuesti){
    if ($kehtiv_parool===$current_password){

How to make PHP code check if inserted current password is correct password from MySQL database

Question

2 answers

solution1
0 2014-04-10 10:20:28

solution2
0 ACCPTED 2014-04-10 10:24:12

How to make PHP code check if inserted current password is correct password from MySQL database

Question

2 answers

solution1 0 2014-04-10 10:20:28

solution2 0 ACCPTED 2014-04-10 10:24:12

solution1
0 2014-04-10 10:20:28

solution2
0 ACCPTED 2014-04-10 10:24:12