simple PHP AJAX : How to call a php script
Question
I'm trying to get my javascript function to use ajax to call a php script. The php script will update a MYSQL table but I've tested the PHP script and it works fine.
This is my function:
function rate()
{
$.ajax({
data: '' ,
url: 'update.php',
method: 'GET',
success: function(msg) {
alert(msg);
}
});
}
and the function is called later with:
rate();
The php script doesn't need any information given to it, it just needs to be called, can anyone point out where I'm going wrong.
5 answers
solution1
1 2014-04-24 11:41:20
Just use like in this example:
<script>
function rate() {
$.get("update.php");
}
</script>
solution2
0 2014-04-24 11:40:26
Here is an example of how I use the ajax call:
$.ajax({
type: "POST",
url: "page_url",
dataType: 'json',
data: {
'date1' : date1,
'call': 'function_name'
},
beforeSend: function(){
$("#loading").show();
},
success : function(response){
},
complete: function(){
$("#loading").hide();
}
})
and on php part I add:
function function_name($request){
your code here
}
if (!empty($_POST['call'])) {
die($_POST['call']($_POST));
}
solution3
0 2014-04-24 11:41:05
If you dont need to pass the data to the PHP page, you can omit 'Data' from the ajax parameters.
<script>
function rate(){
$.ajax({
url: 'update.php',
method: 'POST',
success: function(msg) {
alert(msg);
}
});
}
rate();
</script>
solution4
0 2014-04-24 11:41:27
Have you included jquery library Try this
<script src="http://code.jquery.com/jquery-latest.min.js"
type="text/javascript"></script>
<script>
function rate()
{
$.ajax({
data: '' ,
url: 'update.php',
method: 'GET',
success: function(msg) {
alert(msg);
}
});
}
rate();
</script>
solution5
0 2014-04-24 12:33:51
i show my all working code, try it:
<html>
<head>
<script type="text/javascript" src="/js/jquery-1.8.2.js"></script>
<script>
function rate() {
$.get("update.php");
}
</script>
</head>
<body>
<button onclick="rate()">Click me</button>
</body>
</html>
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