Pointer of a function with variable number of arguments

Question

I have a function with the following prototype:

void func(int an, ...);

And I would like to store the adress of this function and call it later. I have really no idea to how to do that, I desesperatly tried :

void (*funcPtr)(int, ...);  // Declaration
funcPtr = func;     // Storage
(*funcPtr)(3,2,5);      // Call

This code compiles fine, but at execution it does crap, when I enter my function the arguments in my va_list are not the ones I sent.

Thanks in advance

EDIT : Alright, I just forgot the first argument. In my code above, the call line should be replaced with:

(*funcPtr)(3,3,2,5);        // Call

Answer 1

Functions are pointers naturally. So you can simply call:

funcPtr(3,3,2,5);

It looks like you have everything right. If the function does not have variable arguments, it is a really good idea to declare the function pointer with the right "shape" of arguments for protection from passing malformed arguments.