please some one help me
PHP Fatal error: require_once() enter code here[<a href='function.require'>function.require</a>]: Failed opening required '/include/tables.php' (include_path='.:/usr/lib/php:/usr/local/lib/php') in /home2/uaeadver/public_html/include/include.php on line 14
what is this all about i am including the include.php also here
$path=dirname(__FILE__);
global $minimal;
if(!file_exists($path.'/../config.php')) header("Location: install/");
require_once($path.'/../config.php');
if(!isset($config_abs_path) || !isset($config_live_site)) header("Location: install/");
require_once($config_abs_path.'/include/tables.php');
try if both files in same dir
require_once('include.php');
and use to exit dir ../
like
require_once('../include.php');
The way you try to get to your base directory is not really working or the file you try to include does not exist.
Use the function getcwd()
to let return your current work directory if it helps.
Generally, you start your application from always the same path, you could define()
an absolute base path and use that instead:
// define'd constants are always global scope:
define('BASE_PATH', '/home2/uaeadver/public_html/');
require(BASE_PATH . 'include/config.php');
Missing exit;
after Location change:
if(!file_exists($path.'/../config.php')) {
header("Location: install/");
exit;
}
Your codestyle really needs improvement. Don't use globals, try real design patterns and strict coding standards.
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