if(isset($_POST['submit'])) not working
Question
I know there are cases on this, however I tried their method, but it didn't work for me.
Here is the code for isset: I tried placing this statement before <head> tag and within <body> tag but don't think it made a difference. This code resides in the same php file as the the submit button.
<?php if(isset($_POST['action'])) {
echo "testing";
exit();
}?>
Here is the form & submit button within form
<form name="createCaseForm" method = "post" action = "<?php echo url_mgt::getActionURL(); ?>" id="case-form" novalidate="novalidate">
...
<td colspan="1"><button style="float:right;" name="action" type="submit" value="create_case_submit">Submit</button></td>
...
</form>
I'm not sure if using <button> instead <input> of would make a difference. I also did if(count($_POST) > 0) and it didn't work. I'm not sure what I'm doing wrong. When I run the file, it doesn't echo "testing", but instead went straight to the next page. My apologies if it's just a minor matter, but I tried methods posted in forums, but none seems to work.
I've tried to do this:
if(isset($_POST['action']) == 0) {
echo "Testing";
} else {
echo "Testing2";
}
It displays testing when the page is being loaded, however when i click on the submit button, I was hoping to see testing2 being printed. Am i right to say that after clicking the submit button, the page would not reload twice? So there is no way to check if the submit button is being posted?
2 answers
solution1
1 2018-02-19 08:55:37
I was having the same problem as above, if(isset($_POST['submit'])) not working when submitting a form. Setting the name to action didn't work for me. The solution was to assigned the submit to the name field of my form's input element. Here I present a MCVE tested in Firefox.
Kf
index.html
<html>
<body>
<form action="learnphp.php" method="post">
<table border="0">
<tr>
<td>Name</td>
<td align="center"><input type="text" name="username" size="30"/></td>
</tr>
<tr>
<td>City</td>
<td align="center"><input type="text" name="cityaddress" size="30"/></td>
</tr>
<tr>
<td><input id="radio1" type="radio" name="selector"
value="op1" /> </td>
<td><input id="radio2" type="radio" name="selector"
value="op2" /> </td>
</tr>
<tr>
<td colspan="2" align="center"><input type="submit"
name="submit" value="SubmiT"/></td>
</tr>
</table>
</form>
</body>
</html>
learnphp.php
<html>
<head>
<title>Information Gathered</title>
</head>
<body>
<?php
echo "<p>Data processed \"NOW\"</p>";
echo "<p>Let's observe: </p>";
if(isset($_POST['submit'])){
echo "submit set<br>";
echo "Submit value=" . $_POST['submit'] . "<br>";
}
else echo "ERROR submit not set<br>";
if(isset($_POST['selector'])){
echo "Selecter set<br>";
echo "Radial selection value=" . $_POST['selector'] . "<br>";
}
else echo "ERROR Selector not set<br>";
echo "</br>";
?>
</body>
</html>
Output:
Data processed "NOW"
Let's observe:
submit set
Submit value=SubmiT
Selecter set
Radial selection value=op2
solution2
0 2014-05-16 01:40:07
You need a form field named action
<input type="text" name="action"/>
Also, make sure that url_mgt::getActionURL() is outputting the correct URL to submit to
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