I'm trying to use the Xively API with python to update a datastream but occasionally I get a 504 error which seems to end my script.
How can I catch that error and more importantly delay and try again so the script can keep going and upload my data a minute or so later?
Here's the block where I'm doing the uploading.
# Upload to Xivity
api = xively.XivelyAPIClient("[MY_API_KEY")
feed = api.feeds.get([MY_DATASTREAM_ID])
now = datetime.datetime.utcnow()
feed.datastreams = [xively.Datastream(id='temps', current_value=tempF, at=now)]
feed.update()
And here's the error I see logged when my script fails:
Traceback (most recent call last):
File "C:\[My Path] \ [My_script].py", line 39, in <module>
feed = api.feeds.get([MY_DATASTREAM_ID])
File "C:\Python34\lib\site-packages\xively_python-0.1.0_rc2-py3.4.egg\xively\managers.py", >line 268, in get
response.raise_for_status()
File "C:\Python34\lib\site-packages\requests-2.3.0-py3.4.egg\requests\models.py", line 795, >in raise_for_status
raise HTTPError(http_error_msg, response=self)
requests.exceptions.HTTPError: 504 Server Error: Gateway Time-out
Thanks,
PS I've replaced my personal info with [MY_INFO] but obviously the correct data appears in my code.
I usually use a decorator for this:
from functools import wraps
from requests.exceptions import HTTPError
import time
def retry(func):
""" Call `func` with a retry.
If `func` raises an HTTPError, sleep for 5 seconds
and then retry.
"""
@wraps(func)
def wrapper(*args, **kwargs):
try:
ret = func(*args, **kwargs)
except HTTPError:
time.sleep(5)
ret = func(*args, **kwargs)
return ret
return wrapper
Or, if you want to retry more than once:
def retry_multi(max_retries):
""" Retry a function `max_retries` times. """
def retry(func):
@wraps(func)
def wrapper(*args, **kwargs):
num_retries = 0
while num_retries <= max_retries:
try:
ret = func(*args, **kwargs)
break
except HTTPError:
if num_retries == max_retries:
raise
num_retries += 1
time.sleep(5)
return ret
return wrapper
return retry
Then put your code in a function like this
#@retry
@retry_multi(5) # retry 5 times before giving up.
def do_call():
# Upload to Xivity
api = xively.XivelyAPIClient("[MY_API_KEY")
feed = api.feeds.get([MY_DATASTREAM_ID])
now = datetime.datetime.utcnow()
feed.datastreams = [xively.Datastream(id='temps', current_value=tempF, at=now)]
feed.update()
You could throw in a try/except statement in a loop that has a sleep timer for however long you want to wait between tries. Something like this:
import time
# Upload to Xivity
api = xively.XivelyAPIClient("[MY_API_KEY")
feed = api.feeds.get([MY_DATASTREAM_ID])
now = datetime.datetime.utcnow()
feed.datastreams = [xively.Datastream(id='temps', current_value=tempF, at=now)]
### Try loop
feed_updated = False
while feed_updated == False:
try:
feed.update()
feed_updated=True
except: time.sleep(60)
EDIT As Dano pointed out, it would be better to have a more specific except statement.
### Try loop
feed_updated = False
while feed_updated == False:
try:
feed.update()
feed_updated=True
except HTTPError: time.sleep(60) ##Just needs more time.
except: ## Otherwise, you have bigger fish to fry
print "Unidentified Error"
## In such a case, there has been some other kind of error.
## Not sure how you prefer this handled.
## Maybe update a log file and quit, or have some kind of notification,
## depending on how you are monitoring it.
Edit a general except statement.
### Try loop
feed_updated = False
feed_update_count = 0
while feed_updated == False:
try:
feed.update()
feed_updated=True
except:
time.sleep(60)
feed_update_count +=1 ## Updates counter
if feed_update_count >= 60: ## This will exit the loop if it tries too many times
feed.update() ## By running the feed.update() once more,
## it should print whatever error it is hitting, and crash
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