i am having the same problem as faced by many that the script tags are not executed in the jquery ajax response and i already tried the solutions with the 'eval()' method and similar but none is working.Is there any other way to accomplish this. i am sending a ajax request to a file cart.php from home.php
HOME.php
$.ajax({
type:"POST",
url:"cart.php?action=inc&id="+id+"&value="+myvalue+"&linecost="+linecost,
cache:false,
success: function(data)
{
alert(data);
i am actually converting a php array to a javascript array inside cart.php file like this:
CART.php:
processing code here...
<?php
$res=array($val,$cost,$total);
foreach ($res as $a) {
$string .= "\"" . $a . "\", ";
$final = substr($string, 0 ,(strlen($string) - 2));
}
?>
<script>var j = new Array(<?php echo $final; ?>);</script>
Returned data at home.php inside data variable:
<script>var j = new Array("4", "2928", "6708");</script>
Now i just want the elements of this array but it is returning the whole line at the calling file inside the 'success' function..how do i extract the values at the calling file?Any help?
You want to use JSON. Instead of returning the script, you can use json_encode .
echo json_encode($final);
Then to convert the JSON back to an array you can do in JS:
var result=JSON.parse(data);
result
is now a normal JS array containing the same data as in $final
.
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