I would like to filter against query params in my REST API - see django docs on this . However, one parameter I wish to filter by is only available via a model @property
example models.py:
class Listing(models.Model):
product = models.OneToOneField(Product, related_name='listing')
...
@property
def category(self):
return self.product.assets[0].category.name
Here is the setup for my Listing API in accordance with django-filter docs
class ListingFilter(django_filters.FilterSet):
product = django_filters.CharFilter(name='product__name')
category = django_filters.CharFilter(name='category') #DOES NOT WORK!!
class Meta:
model = Listing
fields = ['product','category']
class ListingList(generics.ListCreateAPIView):
queryset = Listing.objects.all()
serializer_class = ListingSerializer
filter_class = ListingFilter
How can I appropriately filter by listing.category? It is not available on the listing model directly.
Use the 'action' parameter to specify a custom method - see django-filter docs
First define a method that filters a queryset using the value of the category parameter:
def filter_category(queryset, value):
if not value:
return queryset
queryset = ...custom filtering on queryset using 'value'...
return queryset
Listing filter should look like this:
class ListingFilter(django_filters.FilterSet):
...
category = django_filters.CharFilter(action=filter_category)
...
For sake of database speed, you should just add the category to your listing model
class Listing(models.Model):
product = models.OneToOneField(Product, related_name='listing')
category = models.ForeignKey(Category)
Then use a post_save signal to keep the field updated
from django.dispatch import receiver
from django.db.models.signals import post_save
@receiver(post_save, sender=Product)
def updateCategory(sender, instance, created, update_fields, **kwargs):
product = instance
product.listing.category = product.assets[0].category.name
product.listing.save()
Then filter by it's name as you would any other field:
class ListingFilter(django_filters.FilterSet):
...
category = django_filters.CharFilter(name='category__name')
...
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