Parse error: syntax error, unexpected '=' in *.php on line?
Question
Every thing is OK .but i can not find why Parse error
my code
<?php
if ($_REQUEST["submit"] == "ChangeTheBgColor")
$bgcolor = strval($_REQUEST["thecolor"]);
else
$bgcolor = "white";
?>
<html>
<body bgcolor="<?php =$bgcolor; ?>" >
<form name= "color" method="get" action="<?php = $_SERVER['PHP_SELF'];?>">
Enter a Color:
<input type="text" name="thecolor" value="">
<input type="submit" name="submit" value="ChangeTheBgColor">
</form>
</body>
</html>
I use devPhp .
Why I get the below Error and how Fix it?
Parse error: syntax error, unexpected '=' in C:\\doc\\demo.php on line 8
1 answers
solution1
2 ACCPTED 2014-06-28 20:34:53
You should write :
<?php echo $_SERVER['PHP_SELF'];?>
And not :
<?php = $_SERVER['PHP_SELF'];?>
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