I use browser-sync ( https://github.com/shakyShane/browser-sync ) in my gulp file for development purposes. I want to use html5mode within my angular app. For that server needs to route multiple url patterns to single html file. Staging and production servers already do that but I would also like to have this up and running during development.
Here is how I run browser-sync
server (part of gulpfile.js
):
gulp.task('serve', function () {
browserSync.init(null, {
server: {
baseDir: [APP_PATH]
}
});
// watch only for app specific codes;
...
});
Just to make it more clear, at my app js I instruct angular to use html5mode for routing:
$locationProvider.html5Mode(true);
Within my APP_PATH I have single index.html
which is served when I access browser-sync
server. What I need is that browser-sync
serves this single file for each paths.
So for example if I try to reach /users/2
path starting from root path everything is fine; however if I refresh page or try to reach /users/2
directly, browser-sync
tells that it cannot find proper document to serve - this is all good and understandable but I wonder if there is any way to tell browser-sync
built-in server to serve one file only. If not, can anyone suggest other options? Should I simply run express server and tell browser-sync
to proxy through it?
You can use https://github.com/tinganho/connect-modrewrite .
var modRewrite = require('connect-modrewrite');
gulp.task('serve', function () {
browserSync.init(null, {
server: {
baseDir: [APP_PATH],
middleware: [
modRewrite([
'!\\.\\w+$ /index.html [L]'
])
]
}
});
// watch only for app specific codes;
...
});
From https://github.com/BrowserSync/browser-sync/issues/204#issuecomment-102623643
First install connect-history-api-fallback
:
npm --save-dev install connect-history-api-fallback
Then add it to your gulpfile.js:
var historyApiFallback = require('connect-history-api-fallback');
gulp.task('serve', function() {
browserSync.init({
server: {
baseDir: "app",
middleware: [ historyApiFallback() ]
}
});
});
In version 2.23.0 you can use single
option, like this:
gulp.task('serve', function () {
browserSync.init(null, {
server: {
baseDir: [APP_PATH]
},
single: true
});
// watch only for app specific codes;
...
});
Reference: https://browsersync.io/docs/options#option-single
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