I'm creating a login / register form for a woocommerce shop.
The default woo template shows two side by side forms, one for new customers to register, one for existing customers to login. IMHO this sucks.
I want to use a button group above a single form that swaps out the login / register forms based on the users selection, this way only one option is presented at a time. Hence, I need to swap content, and apply/remove active classes to the appropriate buttons.
I've done the following:
1.) Added a twitter bootstrap button-group like so:
<div class="col-sm-4 col-sm-offset-4">
<div class="btn-group btn-group-justified">
<div class="btn-group">
<button type="button" id="login_click" class="btn btn-default active" data-toggle="button">Login</button>
</div>
<div class="btn-group">
<button type="button" id="register_click" class="btn btn-default">Register</button>
</div>
</div>
</div>
2.) Wrapped the two forms in bootstrap classes and added IDs for simple targeting.
<div id="login_form" class="col-sm-4 col-sm-offset-4">
// login form
</div>
<div id="register_form" clas="col-sm-4 col-sm-offset-4">
//register form
</div>
I know there are built in jQuery plugins for accomplishing this. I've tried using the .active
class without success. I also tried using data-toggle="button"
and use the .toggle()
method without success. I can't wrap my head around the appropriate jQuery, I either end up with both buttons toggled, or no buttons toggled.
Could someone guide me in the right direction?
You can just set some jQuery to hide/show the form divs:
$('#switch-forms .btn').on('click', function() {
$('#switch-forms .btn').removeClass('active');
$(this).addClass('active');
});
$('#login_click').on('click', function() {
$('#register_form').hide();
$('#login_form').show();
});
$('#register_click').on('click', function() {
$('#login_form').hide();
$('#register_form').show();
});
JS Fiddle: http://jsfiddle.net/ezrafree/HZbvA/
Also, you misspelled the class
attribute on button#register_click
. Updated markup is:
<div class="row">
<div class="col-sm-4 col-sm-offset-4">
<div id="switch-forms" class="btn-group btn-group-justified">
<div class="btn-group">
<button type="button" id="login_click" class="btn btn-default active">Login</button>
</div>
<div class="btn-group">
<button type="button" id="register_click" class="btn btn-default">Register</button>
</div>
</div>
</div>
</div>
<div class="row">
<div id="login_form" class="col-sm-4 col-sm-offset-4">
<p>Login Form</p>
</div>
<div id="register_form" class="col-sm-4 col-sm-offset-4">
<p>Register Form</p>
</div>
</div>
For anyone interested I made it work. Not the "bootstrap way" but it works as desired. Someone with better jQuery chops could certainly simplify this.
<script>
$(document).ready(function() {
var login_btn = $('#login_click');
var register_btn = $('#register_click');
var register_form = $('#registration_form');
var login_form = $('#login_form');
// set defaults
register_form.addClass("hidden");
login_btn.addClass("active");
// events for register button
register_btn.on("click", function(){
login_form.addClass("hidden");
login_btn.removeClass("active");
register_btn.addClass("active");
register_form.removeClass("hidden");
});
//events for login button
login_btn.on("click", function(){
register_form.addClass("hidden");
register_btn.removeClass("active");
login_btn.addClass("active");
login_form.removeClass("hidden");
});
});
</script>
Code updated No jQuery, you could do it with bootstrap collapse. try this
<div class="col-sm-4 col-sm-offset-4">
<div class="btn-group btn-group-justified">
<div class="btn-group">
<button type="button" id="login_click" class="btn btn-default" data-toggle="collapse" data-target=".class1">Login</button>
</div>
<div class="btn-group">
<button type="button" id="register_click" class="btn btn-default" data-toggle="collapse" data-target=".class1">Register</button>
</div>
</div>
</div>
<div class="col-sm-4 col-sm-offset-4">
<div class="class1 collapse in">123</div>
<div class="class1 collapse">321</div>
</div>
cannot comment in feed. there right way to use toggleClass not good
$('#switch-forms .btn').on('click', function() {
$('#switch-forms .btn').removeClass('active');
$(this).addClass('active');
});
good
$('#switch-forms .btn').on('click', function() {
$('#switch-forms .btn').toggleClass('active');
});
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