I have this code
function checkAlerts() {
secondsSinceLoad += 1;
for(var mj = 0 ; mj <= alertList.length; mj++) {
if(alertList[mj]['time'] < secondsSinceLoad && alertList[mj]['time'] > -1 ) {
alertmsg = alertList[mj]['type'] + ":" + alertList[mj]['name'] + "\n" +alertList[mj]['subtitle']+ "\n"+ alertList[mj]['description'] + "\n\n";
window.open(alertList[mj]['redirect'],"name1","width=800,height=500,toolbar=no,location=no,menubar=no,copyhistory=no");
}
}
alertsTimeoutId = setTimeout("checkAlerts()",1000);
}
This is a scheduled popup. It creates a pop-up correctly, however if there are more than 1 scheduled pop-up at same time then only 1 pop-up is shown.
PS I'm presuming it's because the "parent popup has same window opened"
Help is appreciated.
Thanx.
Browsers ban the opening of multiple popups in a loop to stop malicious sites bombing users with lots of new windows.
Work around it by avoiding popups and displaying all your content in a single window.
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