I have the following HTML fragment:
>>> a
<div class="headercolumn">
<h2>
<a class="results" data-name="result-name" href="/xxy> my text</a>
</h2>
I am trying to select header column only if attribute data-name="result-name"
I've tried:
>>> a.select('a["data-name="result-name""]')
This gives:
ValueError: Unsupported or invalid CSS selector:
How can I get this working?
You can simply do this :
soup = BeautifulSoup(html)
results = soup.findAll("a", {"data-name" : "result-name"})
Source : How to find tags with only certain attributes - BeautifulSoup
html = """
<div class="headercolumn">
<h2>
<a class="results" data-name="result-name" href="/xxy> my text</a>
</h2>
"""
from bs4 import BeautifulSoup
soup = BeautifulSoup(html)
for d in soup.findAll("div",{"class":"headercolumn"}):
print d.a.get("data-name")
print d.select("a.results")
result-name
[<a class="results" data-name="result-name" href="/xxy> my text</a></h2>"></a>]
select classes or ids
soup.select('a.gamers') # select an `a` tag with the class gamers
soup.select('a#gamer') # select an `a` tag with the id gamer
select single attr:
soup.select('a[attr="value"]')
select multiple attr:
attr_dict = {
'attr1': 'val1',
'attr2': 'val2',
'attr3': 'val3'
}
soup.findAll('a', attr_dict)
you can use any CSS selector in soup.select
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