I have my AJAX code here
$("#add-student").click(function(e) {
e.preventDefault();
formData = $("#student-form").serialize();
if (cleanFormInput()) {
sendTheInfo(formData);
} else {
shakeForm();
}
});
function sendTheInfo(formData) {
$.ajax({
type: "POST",
url: "../classes/ajax/postNewStudent.php",
data: formData,
statusCode: {
404: function() {
alert( "page not found" );
}
},
success: function(formData) {
console.log("New student submitted:\n" + formData);
//clearForms();
},
error: function(result, sts, err) {
console.warn("Connection error:\n" + err + " : " + sts);
console.log(result);
shakeForm();
},
complete: function() {
console.log("Everything complete");
}
});
}
Always without fail outputs this error: Connection error: SyntaxError: Unexpected end of input : parsererror
But still gives the complete message: Everything complete
Update, PHP code here:
require '../../core/init.php';
require '../../classes/Config.php';
header('Content-Type: application/json');
if (!empty($_POST)) {
$id = $_POST["sid"];
$first = $_POST["first"];
$last = $_POST["last"];
$fav = "0";
$sql = "INSERT INTO `students` (`id`, `first`, `last`, `active`) VALUES ('{$id}', '{$first}', '{$last}', '{$fav}')";
$link = mysql_connect(Config::get('mysql/host'),Config::get('mysql/username'),Config::get('mysql/password')) or die("could not connect");;
mysql_select_db(Config::get('mysql/db'), $link);
$result = mysql_query($sql, $link);
if ($result) {
header('Content-Type: application/json');
$student_data = $id . $first . $last . $fav;
echo json_encode($student_data);
}
}
I'm a bit confused, am I doing my ajax set up wrong? Or is it something else in by backend code wrong? I'm using MySQL and jQuery 2.0.3
Updated code here: here
removed my old answer. I don't think it is an ajax/javascript error. it's definitely a PHP error. It's this lines:
$student_data = $id . $first . $last . $fav;
echo json_encode($student_data);
You $student_data is not an array, it's just a string. You need to pass an array into the json_encode
function
I have had a look at your code. I saw that from the PHP side you are sending a JSON object. but you didn't specified the return dataType for the response. Try to add the dataType in the ajax call. Maybe that will solve the problem
function sendTheInfo(formData) {
$.ajax({
type: "POST",
url: "../classes/ajax/postNewStudent.php",
data: formData,
dataType : 'json',
statusCode: {
404: function() {
alert( "page not found" );
}
},
success: function(formData) {
console.log("New student submitted:\n" + formData);
//clearForms();
},
error: function(result, sts, err) {
console.warn("Connection error:\n" + err + " : " + sts);
console.log(result);
shakeForm();
},
complete: function() {
console.log("Everything complete");
}
});
}
It should be noted that the Ajax COMPLETE method will fire even if the back end does not return a result.
complete: function() {
console.log("Everything complete");
}
will thus show the log'ed entry every time an ajax call is 'finished executing', even if the submit failed.
I would also suggest NOT having 2 headers or the same declaration (you have one up top, and one in the if(result) call.
In a comment thread, you pointed out that you're working on the server but not locally, And thus that implies you have some pathing issues. Check your
../
relative path style urls and make sure that you have the same basepoints.
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.