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Find and select first blank cell in column B with Excel vba

The below code works fine to find the first empty cell in a given column (here column B). But what I need is a code to find the first blank cell in that column.

Sub macro1()
    Dim sourceCol As Integer, rowCount As Integer, currentRow As Integer
    Dim currentRowValue As String
    sourceCol = 2   'column B has a value of 2
    rowCount = Cells(Rows.Count, sourceCol).End(xlUp).Row
    'for every row, find the first blank cell and select it
    For currentRow = 1 To rowCount
        currentRowValue = Cells(currentRow, sourceCol).Value
        If IsEmpty(currentRowValue) Or currentRowValue = "" Then
            Cells(currentRow, sourceCol).Select
        End If
    Next
End Sub

Also, it should start looking from row 10 instead of row 1.

Can somebody rewrite this code to do this?

Could something like this be what you're looking for:

Sub test()
Dim ws As Worksheet

Set ws = ActiveSheet

For Each cell In ws.Columns(2).Cells
    If IsEmpty(cell) = True Then cell.Select: Exit For
Next cell
End Sub

This will run through each cell in column B in the active worksheet and select the first empty one it comes across. To set the sheet to a particular one Change Set ws = ActiveSheet to Set ws = Sheets("EnterSheetNameHere")

Or you could try using:

Sub test()
Dim ws As Worksheet

Set ws = ActiveSheet

For Each cell In ws.Columns(2).Cells
     If Len(cell) = 0 Then cell.Select: Exit For
Next cell
End Sub

My problem is solved by using the following code.

Sheets("sheet1").Select
Dim LR2 As Long, cell2 As Range, rng2 As Range
With Sheets("sheet1")
    LR2 = .Range("B" & Rows.Count).End(xlUp).Row
    For Each cell2 In .Range("B8:B" & LR2)
        If cell2.Value <> "" Then
            If rng2 Is Nothing Then
                Set rng2 = cell2
            Else
                Set rng2 = Union(rng2, cell2)
            End If
        End If
    Next cell2
    rng2.Select
End With

Just my two cents.

The function will look for the first encountered BLANK cell in a range, so it should work with columns and rows.

'Find first BLANK cell in a given range, returnt a range (one cell)
Function FirstBlank(ByVal rWhere As Range) As Range

    Dim vCell As Variant
    Dim answer As Range
    Set answer = Nothing

    For Each vCell In rWhere.Cells

        If Len(vCell.Formula) = 0 Then

            Set answer = vCell
            Exit For

        End If

    Next vCell

    Set FirstBlank = answer

End Function

And then do whatever you want with the cell.

Try this code to select the first empty cell below cell B10. But it requires B10 and B11 to be pre-occupied.

Range("B10").End(xlDown).Offset(1, 0).Select

or

Range("B100000").End(xlUp).Offset(1, 0).Select

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