Having issue with detect iPhone 6/Plus on simulator

Question

I am trying to build a version of my app specifically for iPhone 6 and 6 Plus , whereas I don't have any hardware , I have to test on the simulator ! but it seems , simulator has a strange bug ! first and for most I get screen resolutions and scales , by this code :

    UIScreen *mainScreen = [UIScreen mainScreen];
NSLog(@"Screen bounds: %@, Screen resolution: %@, scale: %f, nativeScale: %f",
      NSStringFromCGRect(mainScreen.bounds), mainScreen.coordinateSpace, mainScreen.scale, mainScreen.nativeScale);

so here is how detect iPhone 6 and 6Plus (Portrait mode):

#define iPhone6 ([[UIDevice currentDevice] userInterfaceIdiom] == UIUserInterfaceIdiomPhone && [UIScreen mainScreen].bounds.size.height == 667)

#define iPhone6Plus ([[UIDevice currentDevice] userInterfaceIdiom] == UIUserInterfaceIdiomPhone && [UIScreen mainScreen].bounds.size.height == 736)

the problem is ! when I lunch my app on iPhone6/Plus simulator , compiler gives me the sceen information of iPhone 4" display :

    2014-09-28 12:32:08.153 WOD[2924:42290] 
Screen bounds: {{0, 0}, {320, 568}}, Screen resolution: <UIScreen: 0x7fa15be0f9b0; bounds = {{0, 0}, {320, 568}}; mode = <UIScreenMode: 0x7fa15bd0d4a0; 
size = 640.000000 x 1136.000000>>, scale: 2.000000, nativeScale: 2.000000

But it works fine on new project ! (I cannot create a new project and start over again !). I cleaned code , delete build folder , change project's name ,and reset Simulator contents setting but still gives me the information of 4" display ! .

I have checked this Q/A but answers require a real device !

Answer 1

The main reason I faced with this problem was I build my application with Xcode 5 and open it with Xcode 6

Solution :

Add Launch Image for Retina HD 5.5 and 4.7 :

Now you can detect iPhone 6/Plus on simulator without having a real device :

#define iPhone6 ([[UIDevice currentDevice] userInterfaceIdiom] == UIUserInterfaceIdiomPhone && MAX([UIScreen mainScreen].bounds.size.height,[UIScreen mainScreen].bounds.size.width) == 667)
 #define iPhone6Plus ([[UIDevice currentDevice] userInterfaceIdiom] == UIUserInterfaceIdiomPhone && MAX([UIScreen mainScreen].bounds.size.height,[UIScreen mainScreen].bounds.size.width) == 736)

Answer 2

Just in case you need to detect iPhone 6/6Plus in landscape, use this.

 #define iPhone6 ([[UIDevice currentDevice] userInterfaceIdiom] == UIUserInterfaceIdiomPhone && MAX([UIScreen mainScreen].bounds.size.height,[UIScreen mainScreen].bounds.size.width) == 667)
 #define iPhone6Plus ([[UIDevice currentDevice] userInterfaceIdiom] == UIUserInterfaceIdiomPhone && MAX([UIScreen mainScreen].bounds.size.height,[UIScreen mainScreen].bounds.size.width) == 736)