In _form i have to upload some pictures and everything is working fine but what im missing is when i select my picture i want to view that picture on the page (before saving and while im inserting the data), so i was trying to get the full path of that picture in order to put it in an image src.
What i already did is showing that picture on Edit but i want to view that picture on the create form.
Here is some of my code.
<div class="row">
<?php echo $form->labelEx($model, 'screenshot2'); ?>
<?php
if (!empty($model->app_name)){
echo "<img src='/apps/$model->app_name/$model->app_name" . "_2.jpg'
width=100px height=80px style='float:left' />
<div style='clear:both'></div>";
}
?>
<?php echo $form->fileField($model, 'screenshot2');
//i want to put the image here
print_r($model->image);//This shows the picture name not the path
?>
<?php echo $form->error($model, 'screenshot2'); ?>
</div>
Any help with getting the path or another way to do it would be appreciated because i didnt find any.
I suppose that you'd like to display "preview" of the image, as soon as some file is selected at the file field.
<?php echo $form->fileField($model, 'screenshot2', array('id' => 'screenshot2')); ?>
<img id="preview" src="" />
<script src="https://code.jquery.com/jquery-2.1.1.min.js"></script>
<script>
(function(){
$('#screenshot2').on('change', function(evt){
if (0 < evt.target.files.length) {
// get file object which is seled by user
var _image = evt.target.files[0];
var _reader = new FileReader();
_reader.onload = function(evt) {
$('#preview').attr('src', evt.target.result);
};
_reader.readAsDataURL(_image);
} else {
$('#preview').attr('src', null);
}
});
})();
</script>
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