I'm binding a ListBox
to an ICollectionView
defined on the ViewModel (VM from now). I have a property for the selected item ( SelectedFoo
) that is set to be the first in the VM constructor.
When someone enters text in a textbox, I filter the collection based on that input (so far, so good).
How can I set the selected index to be the first item in the collection after some filtering was applied? I can't bind to the first object in the ICollectionView
from the code.
Any ideas?
Here's some stripped down code, including the List
, the ICollectionView
that I bind to in the XAML, and the code that filters is in the FooFilterString
which is updated as the user types into the text box.
// This is the underlying list
public List<Foo> FooList
{
get { return _fooList; }
set
{
if (Equals(value, _fooList)) return;
_fooList = value;
RaisePropertyChanged();
}
}
private List<Foo> _fooList;
// This is what the list box binds to
public ICollectionView FooListView
{
get { return _fooListView; }
set
{
if (Equals(value, _fooListView)) return;
_fooListView = value;
RaisePropertyChanged();
}
}
private ICollectionView _fooListView ;
// This is bound to from the XAML, as user types, it will filter the list.
// I want to bind to the first item of the filtered list.
public string FooFilterString
{
get { return _fooFilterString; }
set
{
_fooFilterString = value;
FooListView.Filter = (s => some_logic); // <-- filters the list
/*
* How can I set the selected index here ?!
*/
}
}
private string _fooFilterString;
// I Bind to this, and want to set this after filtering. First time, I just
// set it to the first item from the FooList, but after filtering, I'm loosing
// the selection
public Foo SelectedFoo {
get { /*...*/ }
set { /*...*/ }
}
private Foo _selectedFoo;
To sum up comments to select first item from ICollectionView
you can use ICollectionView.MoveCurrentToFirst()
FooListView.Filter = s => some_logic;
FooListView.MoveCurrentToFirst()
you'll also need to enable IsSynchronizedWithCurrentItem
<ListBox ... IsSynchronizedWithCurrentItem="True">
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