Can not perform swipe-to-delete on UITableView if it is in UIScrollView

Question

我创建了一个UITableView，在正常情况下可以对其表单元格执行滑动删除操作，但是当我将UITableView放入可以水平滚动的UIScrollView时，外部的滚动视图将吞没swipe事件，因此将swipe-to -delete不可行。

Answer 1

I'm sorry to tell you that you have to give up one for your function since the two functions rely on the same gesture.
If you want to keep the swipe-delete, set the outer scrollview.scrollEnabled = NO . I think that would help.

If not, have a button to start the tableview edit mode. That will make you delete cell with the scrollview can be slided.

Answer 2

I've finally found solution!

Subclass the outer UIScrollView, and override a method

-(BOOL)gestureRecognizerShouldBegin:(UIGestureRecognizer *)gestureRecognizer

@interface AllowSwipeScrollView : UIScrollView

@end

@implementation AllowSwipeScrollView

-(BOOL)gestureRecognizerShouldBegin:(UIGestureRecognizer *)gestureRecognizer{
    BOOL inTableViewCell = .... // check the current touch is in table view cell

    if (inTableViewCell) {
        return NO;
    }else{
        return [super gestureRecognizerShouldBegin:gestureRecognizer];
    }
}

@end

And make sure the UITableView instances are in AllowSwipeScrollView.

Answer 3

try This condition

if (ScrollView == self.tableView) return;

in scrollviewdidscroll method.