How do I graph my equation in R

Question

I have the following equation that I would like to graphy for y values between 0 - 20. However I am not sure how to set the data up to use the function plot (x,y) .

I first defined my y values as:

y <- data.frame(x = c(1:20))

And then my x values as:

x<- (exp (-1.973 + 0.598*y) )/ (1+ exp (-1.973+ 0.598*y)) 

I get back this error when using plot(x,y)

Erreur dans stripchart.default(x1, ...) : méthode graphique incorrecte (error in stripchart: method graphic incorrect)

any tips?

Answer 1

You could simply create a data.frame object with y and x value, and afterwards plot it.

y <- c(1:20)
x <- exp (-1.973 + 0.598*y) / 1+ exp (-1.973+ 0.598*y)
df <- data.frame(y = y, x = x)
plot(df$y, df$x)

Answer 2

如果要在范围[0,20]上绘制方程exp(-1.973+0.598*x)/(1+exp(-1.973+0.598*x)) ，最简单的方法是使用函数curve ，这样不必定义ay或x向量，因为它直接采用表达式：

curve(exp(-1.973+0.598*x)/(1+exp(-1.973+0.598*x)),from=0,to=20)

Answer 3

由于x和y都是数据帧，因此必须在绘制前用[[提取第一列。

plot(x[[1]], y[[1]])