I'm trying to use Apache's ErrorDocument
to handle client and server errors by passing them to error.php
.
.htaccess
ErrorDocument 400 /error.php
...
ErrorDocument 404 /error.php
...
ErrorDocument 511 /error.php
error.php
var_dump(http_response_code());
So, I point my browser to mywebsite.com/noeutdhoaeu
, which does not exist. The response from the server is 404 Not Found
, as you would expect. But PHP gives me 200
.
What gives?
Edit : I have this same exact code on my Apache-based localhost and it works just fine. That is the reason I am asking this question. PHP is completely aware that a 404 error has occurred in my local environment. On my hosted environment, however, PHP has no idea.
This function is basically a setter/getter for PHP 's response code. Without parameters, this function returns the currently set response code by PHP . Since the default response code is 200
, without setting a different code by first passing a parameter, 200
will always be returned.
See this example in the manual :
var_dump(http_response_code()); // int(200) - default
http_response_code(404); // set a new code
var_dump(http_response_code()); // int(404) - new code
It's also worth noting that header()
calls may also affect the return value of this function, for example:
header('http/1.0 404 not found');
var_dump(http_response_code()); // int(404) - new code
As @Boaz said, PHP doesn't know what Apache is going to set later.
You could use this approach to use the error code in PHP:
ErrorDocument 400 /error.php?error=400
ErrorDocument 401 /error.php?error=401
...
And in PHP test $_GET["error"]
.
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