I keep getting the error "Subscripted assignment dimension mismatch" for the x_values line. I've tried switching parenthesis but I can't figure it out. I'm not very good with MATLAB and this code is super long so I didn't want to post the whole thing.
for m = 1:num_part;
for n = 2:num_steps;
x_values(m,n) = x_values(m,n-1)+ stride_length .* (cos(step_angle(m,n)));
y_values(m,n) = y_values(m,n-1)+ stride_length .* (sin(step_angle(m,n)));
r_values (m,n) = sqrt(x_values(m,n).^2 + y_values(m,n).^2);
if bound_cross(m)~=0;
continue;
elseif bound <= r_values(m,n);
bound_cross (m,1) = n;
end
end
As I figured out, error is in the variable bound_cross
. If you have defined it in the way you replied in the comment as ' bound_cross = [num_part, 1]
', it creates a 1*2 element matrix only. But if you needed a 20*1 matrix, you have to specifically define it. Jut to check the code, I used an empty matrix and it worked fine.
num_part = 20;
num_steps = 1000;
stride_length = 100;
bound = 1;
bound_cross = ones(num_part, 1) ;
x_values = zeros(num_part, num_steps);
y_values = x_values;
r_values = x_values;
step_angle = x_values;
for m = 1:num_part;
for n = 2:num_steps;
x_values(m,n) = x_values(m,n-1)+ stride_length .* (cos(step_angle(m,n)));
y_values(m,n) = y_values(m,n-1)+ stride_length .* (sin(step_angle(m,n)));
r_values (m,n) = sqrt(x_values(m,n).^2 + y_values(m,n).^2);
if bound_cross(m)~=0;
continue;
elseif bound <= r_values(m,n);
bound_cross (m,1) = n;
end
end
end
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