Let
reason <- c("v","v","v","v","v","s","s","s","v","v","v","s","s")
location <- c("c","c","c","c","c","c","c","c","h","h","h","h","h")
zero_one <- c(1,1,0,1,1,1,1,0,1,0,0,1,0)
df <- data.frame(reason, location, zero_one)
Is there an easy way to convert "df" to "DF", where "DF" has the following shape:
reason location #zeros #ones
v c 1 4
s c 1 2
v h 2 1
s h 1 1
You could do this using dcast
library(reshape2)
dcast(transform(df, zero_one= factor(zero_one, levels=0:1,
labels=c('zeros', 'ones'))), ...~zero_one, value.var='zero_one', length)
# reason location zeros ones
#1 s c 1 2
#2 s h 1 1
#3 v c 1 4
#4 v h 2 1
Or using data.table
(similar approach as @jalapic's)
setDT(df)[,list(zeros=sum(!zero_one), ones=sum(!!zero_one)),
.(reason, location)][]
# reason location zeros ones
#1: v c 1 4
#2: s c 1 2
#3: v h 2 1
#4: s h 1 1
Or in base R
aggregate(cbind(zeros=!zero_one, ones=!!zero_one)~., df, FUN= sum)
# reason location zeros ones
#1 s c 1 2
#2 v c 1 4
#3 s h 1 1
#4 v h 2 1
You can do it with dplyr
very simply:
library(dplyr)
df %>%
group_by(reason,location) %>%
summarize(zeros = sum(zero_ones==0), ones = sum(zero_ones==1))
# reason location zeros ones
#1 s c 1 2
#2 s h 1 1
#3 v c 1 4
#4 v h 2 1
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