Post variables to php file and load result on same page with ajax
Question
I have tried searching quite a bit but can't seem to make anything work.
I am trying to make a form that sends info to a PHP file and displays the output of the PHP file on the same page.
What I have so far:
HTML:
<html>
<form id="form">
<input id="info" type="text" />
<input id="submit" type="submit" value="Check" />
</form>
<div id="result"></div>
</html>
JS:
<script type="text/javascript">
var info= $('#info').val();
var dataString = "info="+info;
$('#submit').click(function (){
$.ajax({
type: "POST",
url: "/api.php",
data: dataString,
success: function(res) {
$('#result').html(res);
}
});
});
</script>
PHP:
<?php
$url = '/api.php?&info='.$_POST['info'];
$reply = file_get_contents($url);
echo $reply;
?>
When I set the form action to api.php, I get the result I am looking for. Basically what I want is to see the same thing in the "result" div as I would see when the api.php is loaded.
I cannot get any solutions to work.
3 answers
solution1
1 2015-04-21 23:49:19
Your click event is not stopping the actual transaction of the page request to the server. To do so, simply add "return false;" to the end of your click function:
$('#submit').click(function (){
$.ajax({
type: "POST",
url: "/api.php",
data: dataString,
success: function(res) {
$('#result').html(res);
}
});
return false;
});
Additionally, you should update the type="submit" from the submit button to type="button" or (but not both) change .click( to .submit(
solution2
0 2015-04-22 01:06:15
Thanks everyone for your help, I have it working now.
I was doing a few things wrong:
I was using single quotes in my php file for the URL and also for the $_POST[''] variables.
I needed to add return false; as Steve pointed out.
I did not have a "name" for the input elements, only an ID.
solution3
0 2015-04-22 01:18:32
I think Your code evaluate dataString before it is filled with anything. Try to put this into function of $.ajax . The code below.
/* ... */
$('#submit').click(function (){
$.ajax({
var info= $('#info').val();
var dataString = "info="+info;
/* ... */
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