Django 1.3 specify the template to use in argument with inclusion_tag

Question

I am currently having 2 templatetags for nearly the same thing:

@register.inclusion_tag('content.html')
def content(key, lazy=False, params=''):
    return {'key': key, 'lazy': js_bool(lazy), 'params': params}

@register.inclusion_tag('spec.html')
def spec(key, lazy=False, params=''):
    return {'key': key, 'lazy': js_bool(lazy), 'params': params}

I'd like to merge them as only the template to use change, how could I do that ?

Answer 1

You can do it this way:

def tag(key, lazy=False, params=''):
    return {'key': key, 'lazy': js_bool(lazy), 'params': params}

register.inclusion_tag('content.html', name='content')(tag)
register.inclusion_tag('spec.html', name='spec')(tag)

Python decorators are nothing more than syntactic helpers, you can replace

@decorator
def function():
    pass

by

def function():
    pass
function = decorator(function)