How to create today, tomorrow and yesterday with MySQL

Question

first of all I have searched the forum for getting an answer to my problem. I am creating a weekly schedule with PHP & MySQL and the problem is that I can not figure out how to setup the case statement when the actual day is Sunday and I need to set Monday as Tomorrow. Here is my simple MySQL table week

Fields: dayid(int,primary,auto-increment),day(varchar(25))
Data: (1,'Monday'),(2,'Tuesday'),(3,'Wednesday'),(4,'Thursday'),
      (5,'Friday'),(6,'Saturday'),(7,'Sunday');

Here is my php code:

$today = date("N");
$query = "SELECT *,case when dayid = '$today' THEN 'Today'
                        when dayid = '$today' + 1 THEN 'Tomorrow'
                        when dayid = '$today' - 1 THEN 'Yesterday'
                        ELSE day END days FROM week ";
$results = mysqli_query($link, $query);
while ($r = mysqli_fetch_array($results)) {
echo '<p>'.$r['days'].'</p>'; }

Like I wrote before I can not figure out how to set it up so when $today = 7 (Sunday) that Monday will say Tomorrow and the other way around so when it´s Monday that it says yesterday instead of Sunday. Hopefully someone can help me solve this.

Thank you in advance!

Answer 1

You need to use IF to wrap around at the end of the week:

CASE dayid
    WHEN $today THEN Today
    WHEN IF($today = 7, 1, $today + 1) THEN 'Tomorrow'
    WHEN IF($today = 1, 7, $today - 1) THEN 'Yesterday'
    ELSE day
END days