Angular ng-options remove blank option and select the first option only

Question

I am using AngularJS to populate my select options content dynamically from an array of objects in my controller. My objects has a property named userProfileName .

How would it be possible to remove the blank option that I am getting at the top?

Also, I would want to select the first profile Profile 1 by default. How can this be done?

My Snippet of code is here:

<select id="requestorSite" 
                             ng-model="selectedUserProfile"
                             ng-options="userProfile.userProfileName for userProfile in userProfiles"
                             ng-selected=""
                             class="form-control displayInlineBlock width40per marginLeft15">
                            </select>

My controller has

$scope.userProfiles

As the array of object and each object has userProfileName attribute.

Below is the screen shot:

I would like to remove the blank option at the top and also have by default Profile 1 selected.

Thanks, Ankit

Answer 1

Do this :)

In your controller :

 function myCtrl ($scope) {
   $scope.userProfiles = [
     {id: 10, name: 'Carton'},
     {id: 27, name: 'Bernard'},
     {id: 39, name: 'Julie'},
  ];

   $scope.selectedUserProfile= $scope.userProfiles[0]; // Set by default the   value "carton"
  };

In your page :

      <select  id="requestorSite" ng-model="selectedUserProfile" ng-options="userProfile as userProfile.name for userProfile in userProfiles">
            </select>

CodePen: http://codepen.io/anon/pen/qdOGVB

Answer 2

This has several solution. The following worked best for me. Just initialize the model with the first value. The ng-init="myItem = items[0].name" does the trick

<select ng-if="items" ng-init="myItem = items[0].name" ng-model="myItem">
     <option ng-repeat="item in items" ng-value="item.name">{{item.name}}</option>
</select>