Add photo into database php mysql

Question

I want to insert image into my database table. I have search google but I can not insert image into my database. My database field name is 'photo' and data type is 'blob'. please help...

here is my code:

<?php
$id="";
$opr="";
if(isset($_GET['opr']))
    $opr=$_GET['opr'];

if(isset($_GET['rs_id']))
    $id=$_GET['rs_id'];
//--------------add data-----------------   
if(isset($_POST['btn_sub'])){
    $fac_name=$_POST['factxt'];
    $batch=$_POST['batchtxt'];
    $reg=$_POST['regtxt'];
    $s_name=$_POST['snametxt'];
    $f_name=$_POST['fnametxt'];
    $gender=$_POST['gender']
    $phone=$_POST['phonetxt'];
    $mail=$_POST['emailtxt'];
    $photo=$_POST['photos'];    

    $sql_ins=mysql_query("INSERT INTO stu_tbl 
                          VALUES(
                            NULL,
                            '$fac_name',
                            '$batch',
                            '$reg',
                            '$s_name',
                            '$f_name' ,
                            '$gender',
                            '$phone',
                            '$mail',
                            '$photo'
                            )
                    ");
    if($sql_ins==true)
        $msg="1 Row Inserted";
    else
        $msg="Insert Error:".mysql_error();
}
?>

<!DOCTYPE html>
<head>
</head>
<body>
    <h2 class="custom-light-heading" align="center">Add New Student</h2>
    <hr>
    <form method="post">
        <table>
            <tr>
                <td>Faculties's Name</td>
                <td>
                    <input type="text" />
                </td>
            </tr>
            <tr>
                <td>Batch:</td>
                <td>
                    <input type="text" class="form-control" name="batchtxt" id="textbox" />
                </td>
            </tr>

            <tr>
                <td>Registration:</td>
                <td>
                    <input type="text" class="form-control" name="regtxt" id="textbox" />
                </td>
            </tr>
            <tr>
                <td>Student Name:</td>
                <td>
                    <input type="text" class="form-control" name="snametxt" id="textbox" />
                </td>
            </tr>
            <tr>
                <td>Father's Name:</td>
                <td>
                    <input type="text" class="form-control" name="fnametxt" id="textbox" />
                </td>
            </tr>
            <tr>
                <td>Gender:</td>
                <td>
                    <input type="radio" name="gender" value="Male" checked="checked" />Male
                    <input type="radio" name="gender" value="Female" />Female
                </td>
            </tr>
            <tr>
                <td>Phone:</td>
                <td>
                    <input type="text" class="form-control" name="phonetxt" id="textbox" />
                </td>
            </tr>
            <tr>
                <td>E-mail:</td>
                <td>
                    <input type="text" class="form-control" name="emailtxt" id="textbox" />
                </td>
            </tr>
            <tr>
                <td>photo:</td>

                <td>
                    <input type="File" name="photos" />
                </td>
            </tr>
            <tr>
                <td>

                    <input type="submit" name="btn_sub" class="btn btn-success" value="Add" id="button-in" />
                </td>
            </tr>
        </table>
        </div>
    </form>
    </div>
    <?php ?>
</body>
</html>

Answer 1

As I said in comments: I don't see an opening <form> tag. plus it needs to be a post method with a valid enctype when working with files.

This being in your original posted question:

https://stackoverflow.com/revisions/30152576/1

Add the following to your code, replacing the action to your own.

<form action="handler.php" method="post" enctype="multipart/form-data">

If doing this inside the same file, you can just do action="" as "self".

Also this $photo=$_POST['photos']; needs to be $photo=$_FILES['photos']; using $_FILES and not $_POST since it's a file and not a text input or anything other than a file.

Then this <input type="text" /> for Faculties's Name you don't have a name attribute for it, and seems related to $_POST['factxt'] .

So modify it to <input type="text" name="factxt" /> .

Using error reporting would have caught that. See my notes below about it.

Sidenote: Your present code is open to SQL injection . Use mysqli with prepared statements , or PDO with prepared statements , they're much safer .

Add error reporting to the top of your file(s) which will help find errors.

<?php 
error_reporting(E_ALL);
ini_set('display_errors', 1);

// rest of your code

Sidenote: Error reporting should only be done in staging, and never production.

Footnotes:

You should use proper bracing techniques. Many of your conditional statements don't have braces if(condition){...} and this could cause havoc with your code.
If you truly want to check if your query was successful, use mysql_affected_rows() .
If you see notices about mysql_ being deprecated, then it will be time for you to switch over to mysqli_ or PDO, which you should be using anyway, since it will be removed from future PHP releases.

Add photo into database php mysql

Question

1 answers

solution1
4 ACCPTED 2015-05-10 14:41:45

Add photo into database php mysql

Question

1 answers

solution1 4 ACCPTED 2015-05-10 14:41:45

solution1
4 ACCPTED 2015-05-10 14:41:45