From this post they said that it is kind of a bug in ios 7 and 8 - Button in UITableViewCell
does not change to highlighted when tapped. Here I post one answer for this in Objective-C:
Create a custom UITableView
subclass and custom UITableViewCell
subclass.
Use this sample UITableView
's initWithFrame:
- (id)initWithFrame:(CGRect)frame
{
self = [super initWithFrame:frame];
if (self)
{
// iterate over all the UITableView's subviews
for (id view in self.subviews)
{
// looking for a UITableViewWrapperView
if ([NSStringFromClass([view class]) isEqualToString:@"UITableViewWrapperView"])
{
// this test is necessary for safety and because a "UITableViewWrapperView" is NOT a UIScrollView in iOS7
if([view isKindOfClass:[UIScrollView class]])
{
// turn OFF delaysContentTouches in the hidden subview
UIScrollView *scroll = (UIScrollView *) view;
scroll.delaysContentTouches = NO;
}
break;
}
}
}
return self;
}
Use this sample UITableViewCell
's initWithStyle:reuseIdentifier:
- (id)initWithStyle:(UITableViewCellStyle)style reuseIdentifier:(NSString *)reuseIdentifier
{
self = [super initWithStyle:style reuseIdentifier:reuseIdentifier];
if (self)
{
// iterate over all the UITableViewCell's subviews
for (id view in self.subviews)
{
// looking for a UITableViewCellScrollView
if ([NSStringFromClass([view class]) isEqualToString:@"UITableViewCellScrollView"])
{
// this test is here for safety only, also there is no UITableViewCellScrollView in iOS8
if([view isKindOfClass:[UIScrollView class]])
{
// turn OFF delaysContentTouches in the hidden subview
UIScrollView *scroll = (UIScrollView *) view;
scroll.delaysContentTouches = NO;
}
break;
}
}
}
return self;
}
However I cannot write in Swift. There are some problem:
1) I cannot do
self = super.init(style: style, reuseIdentifier: reuseIdentifier)
Error: Cannot assign to 'self' in a method
2) In Swift, I cannot do
view.class
as in Objective C:
[view class]
I have searched for hours but still cannot get what I want.
Please anyone can answer this in Swift?
在Swift中,要调用超类的指定初始化程序,而不是调用self = [super initWithStyle:style reuseIdentifier:reuseIdentifier]
,而只需使用super.init(style: style, reuseIdentifier: reuseIdentifier)
Thanks to Schemetrical, this is the working version for me. (iOS 7 + 8)
First I wrote a utility function:
class func classNameAsString(obj: AnyObject) -> String {
return _stdlib_getDemangledTypeName(obj).componentsSeparatedByString(".").last!
}
then I subclass UITableView and implement this:
required init(coder aDecoder: NSCoder) {
super.init(coder: aDecoder)
for view in self.subviews {
if (Utility.classNameAsString(view) == "UITableViewWrapperView") {
if view.isKindOfClass(UIScrollView) {
var scroll = (view as UIScrollView)
scroll.delaysContentTouches = false
}
break
}
}
}
I also subclass UITableViewCell and implement this:
required init(coder aDecoder: NSCoder) {
super.init(coder: aDecoder)
for view in self.subviews {
if (Utility.classNameAsString(view) == "UITableViewCellScrollView") {
if view.isKindOfClass(UIScrollView) {
var scroll = (view as UIScrollView)
scroll.delaysContentTouches = false
}
}
}
}
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