calling php function from submit button
Question
I want to pass the value of input field address to php. So that when i click on submit button it will be store in php.
<input type="text" name="address">
<input type="submit" name="go" method="post">
<?php
if($_POST){
if(isset($_POST['go'])){
call();
}else{
echo "Error";
}
}
function call(){
echo "hi";
print(document.address.value);
}
?>
However when i click on button it response nothing.
4 answers
solution1
3 2015-05-20 05:23:25
what you intend to do can be done as below method.
<form method="post" >
<input type="text" name="address">
<input type="submit" name="go">
</form>
<?php
if($_POST){
if(isset($_POST['go'])){
call();
}else{
echo "Error";
}
}
function call(){
echo "hi";
echo $_POST['address'];
}
?>
solution2
3 ACCPTED 2015-05-20 05:25:43
You are mixing PHP and JavaScript. If you want a pure PHP solution you could do something like:
<?php
if(isset($_POST['go'])){
$address = $_POST['address'];
echo $address;
}
?>
<form method="POST">
<input type="text" name="address">
<input type="submit" name="go" method="post">
</form>
With PHP once the form is submitted you can access form values with $_POST so use $_POST['address'] instead of document.address.value
solution3
1 2015-05-20 05:31:49
Try like this,this is working fine as per your requirement:
<html>
<body>
<form action="" method="post">
Address: <input type="text" name="name"><br>
<input type="submit" name="go" value="call" />
</form>
<?php
if (isset($_REQUEST['name'])) {
call();
}
?>
<?php
function call() {
$address= $_POST['name'];
echo "Address:".$address;
exit;
}
Output:-
For output Click here
solution4
0 2015-05-20 05:22:51
use this code
<input type="text" name="address">
<input type="submit" name="go" method="post">
<?php
if($_POST){
if(isset($_POST['go'])){
call();
}else{
echo "Error";
}
function call(){
echo "hi";
echo $_POST['address'];
}
?>
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