Run a setup.py from another Python script, path issue, installing in calling script dir?

Question

First, I've found how to call a script from within an other script in Python, the call works perfectly well, but here's the problem I'm running into :

In order to easy-install my web-app (Bottle) on an another server, I packed inside a /redist rep, with mod_wsgi and PyMySQL source files. What I'm trying to achieve is a kind of "setup.py" file, that will launch the /mod_wsgi/setup.py install file and the same with the PyMySQL setup file.

Here's what I'm doing for PyMySQL for example :

subprocess.call("python3 ./redist/PyMySQL/setup.py install", shell=True)

The instalation runs fine, BUT, I end up with a /build , a /dist and a /PyMySQL.egg-info folders in my app directory, and when I'm trying to launch anything that imports PyMySQL, it told me that the module didn't exist.

If I manually install it (using my terminal I mean, like cd /redist/PyMySQL/ and then py3 setup.py install ), it works great, and the import will then work ...

Any idea ? Am I doing something wrong ?

By advance, thanks :)

Answer 1

I think this would solve your issue : Python specify popen working directory via argument

I suppose in the "./redist/PyMySQL/" directory could be used as parameter because it is where the setup.py is located

try this :

subprocess.Popen("py3 setup.py", cwd='/redist/PyMySQL/')

on my end this works :

subprocess.Popen(['py3','setup.py'], cwd='path-of-my-setup')