Files sorting with version number in Powershell

Question

I have this folder in a directory. With different version on them.

CD1,CD2,CD3,CD4,CD5,CD6,CD7,CD8,CD9,CD11,CD12

I'm new to powershell, can anyone help me to get the latest version folder from the above folders? Here CD12 is the latest folder. I can't use last modified time because I copy them at the same time.

$FolderName=(Get-ChildItem C:\Current\CD |Where-Object {$_.name -like "*CD*"}| sort{$_.name.Substring(2,2)}|Select-Object Name -Last 1).Name)
Write-Host "$FolderName"

I tried the above script and it did not help. Can anyone help me? The next new version is CD13 , and the script should get that folder

Answer 1

You can try something like below

$max_version = Get-ChildItem "C:\Current\" | Where-Object {$_.PSIsContainer} 
| Foreach-Object {$_.Name} | Foreach-object {$_ -replace "CD", ""} 
| measure -maximum | Select-Object -expand Maximum

Write-host ("CD" + $max_version)

Which will result in CD12

Answer 2

You almost have it. When I tried to run your code, I ran into two errors. First, you have an extra ')' at the end of the line causing a syntax error. Second, your 'SubString()' call is failing because you're trying to get the 3rd and 4th characters of a string without a 4th character ("CD1"). You don't need the scriptblock to your Sort command, though. You can just sort on the Name field.

$FolderName = Get-ChildItem C:\7005\Hot-Fix\CD | where Name -like "CD*" | sort Name | Select-Object -Last 1 -ExpandProperty Name

As a side note, this uses the PowerShell 3 syntax for Where-Object and Sort-Object to omit the {} . And it uses the -ExpandProperty parameter to Select-Object , so you don't have to wrap the whole thing in parens to get the Name property.

Answer 3

You could try this:

#requires -v 3
$baseFolder='C:\7005\Hot-Fix\CD'
$folder=dir $baseFolder\CD* -Directory | 
    ? basename -CMatch 'CD\d{1,}' | 
    sort @{e={'{0:0000}' -f [int]($_ -replace '\D')}} -Descending | 
    select -First 1

Notice, I'm considering case sensitive matching; also, $folder contains what you're looking for.