php mysqli prepared statement remove query issue

Question

I have made a page to remove different elements of my site, but for some reason it's not working... Event though i set the fMenu to be i - integer, because it is. When i run the code below, it gives me:

Fatal error : Call to a member function bind_param() on a non-object in C:\\Users\\joonas\\Desktop\\Le Kerouac\\root\\admin\\remove.php on line 44

Code(PHP):

include_once('../php/connDbPrepared.php');
mysqli_set_charset($mysqli, 'utf8');
//Anti mysql injection precautions
$menu = mysqli_real_escape_string($mysqli, $menu);
$sql = "REMOVE FROM menu WHERE fMenu = ?";
$stmt = $mysqli->prepare($sql);
$stmt->bind_param("i", $menu);
if($stmt->execute())
{
    $stmt->close();
    echo '
    <script type="text/javascript">
    window.location.replace("../admin/admintable.php?page=main&message=removeSuccessMenu");
    </script>
    ';
}
else
{
    echo '
    <script type="text/javascript">
    $(document).ready(function()
    {
        $("#screenCover").slideToggle("slow");
        $("#closePopup").click(function()
        {
            $("#screenCover").slideToggle("slow");
            setTimeout(resetPage, 600);
        });
});
function resetPage()
{
    window.location.replace("../admin/admintable.php?page=main");
}
</script>
<div id="screenCover" style="display:none;">
<div id="popup">
<div id="closePopupMain">
<p id="closePopup"><a href="#">X</a></p>
</div>
<p id="failure">Le menu n\'a pas éte enlevée! Cause: Erreur '.mysqli_errno($mysqli).": ".mysqli_error($mysqli).'</p>
</div>
</div>';
}

Answer 1

mysql中没有REMOVE关键字，请使用DELETE：

Delete from menu where fmenu = ?

Answer 2

The correct function name is bindParam() not bind_param()

Change

$stmt->bind_param("i", $menu);

to

$stmt->bindParam("i", $menu);

This will get rid of the error message that you are getting. Then you need to fix your SQL statement.