I have a PandasData Frame that is 26 columns and 100 rows. I want to extract a particular value from column 25 (which is called Unnamed: 24) row 50 and throw it into a list. Is there any way to do this? My columns are called Unnamed: 0, Unnamed: 1, ..., Unnamed: 25; and the rows are just going 0 to 99:
Unnamed 0: ..... Unnamed: 24 Unnamed: 25
0
1
.
.
50 50
.
.
99
and
Numbers = []
I want to append this value 50 to Numbers which is from column 24 row 50.
My data frame is x = xls.parse('excelfile1.xls'), I am parsing a dataframe from an excel spreadsheet
You can use iloc
for this:
Numbers = []
value = df1.iloc[24,50]
Numbers.append(value)
Or as a more general example:
import pandas as pd
import numpy as np
df = pd.DataFrame(index=range(0,5), data=[range(5*i,5*i+5) for i in range(0,5)])
df
:
0 1 2 3 4
0 0 1 2 3 4
1 5 6 7 8 9
2 10 11 12 13 14
3 15 16 17 18 19
4 20 21 22 23 24
and print df.iloc[2,2]
returning 12
For selecting a single value from a DataFrame or Series, at
(label based scalar indexing) and iat
(index based scalar indexing) are generally the fastest.
numbers = []
numbers.append(df.iat(50, 24))
Lets say you had three pairs of numbers representing row and column index values where you want to lookup a value from your DataFrame. You could efficiently accomplish this goal as follows:
pairs = [(10, 20), (20, 25), (30, 30)]
[numbers.append(df.iat(row, col)) for row, col in pairs]
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