How can I limit the number of images shown per page?
Question
I have a certain number of images that are displaying per page. I want to set a maximum limit for the number of images shown on any page, for example setting a property such that no more than eight are shown. I've written this logic in PHP but I'm still seeing all images showing on any given page, ignoring any limit I set. The code:
$counter = 0;
foreach ($device as $value) {
$entry = $value;
echo "<head>";
echo '<script type="text/javascript">',
'window.setInterval(function() { ',
"document.getElementById('$counter').src='/latimage.php?&dev=$entry&random='+new Date().getTime();",
'},1000)',
'</script>';
echo "</head>";
echo "<body onLoad='setTimeout('refresh()',1000)'>";
echo "<td>$entry<img id= '$counter' width='100%' height='auto'></img></td>";
$counter = $counter + 1;
if ($counter == 4 || $counter == 8) {
echo " <tr>";
}
2 answers
solution1
2 2015-07-30 07:25:35
最好的方法是从数据库中仅获取8个图像，而不是一次获取所有图像。使用分页设置每个页面的限制和偏移量。
solution2
1 ACCPTED 2015-07-30 07:50:54
You need to add a $_GET['variable'] ;
Something like this,
if(isset($_GET['last_image'])) {
$last_image = $_GET['last_image'];
}
else {
$last_image = 0;
}
$device[] = //however you get the images
$size_of_array = count($device);
for ($counter = $last_image; $counter < $counter + 8 && $counter < $size_of_array; $counter++) {
$entry = $device[$counter];
echo "<head>";
echo '<script type="text/javascript">',
'window.setInterval(function() { ',
"document.getElementById('$counter').src='/latimage.php?&dev=$entry&random='+new Date().getTime();",
'},1000)',
'</script>';
echo "</head>";
echo "<body onLoad='setTimeout('refresh()',1000)'>";
echo "<td>$entry<img id= '$counter' width='100%' height='auto'></img></td>";
}
Then next button
echo '<a href="myurl.com?last_image='. $counter .'">Next</a>';
This is the basic idea behind a pagination.
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