In bootstrap I have a fixed top nav bar and fixed bottom nav bar. I want to show a large image in the background between the space of those two nav bars and I also want to cover the width of the window. How can I dynamically get the height between the navbars and the width of the window? The window size may change depending on device.So I need it dynamic
Requires jquery:
var viewport = {
width : $(window).width(),
height : $(window).height()
};
//can access dimensions like this:
//viewport.height
Though you won't always get perfect results, different devices behave differently and this gives the viewport dimensions, not the screen dimensions.
Alternatively you could check the width of a data-role="page"
element to find the device-width (since it's set to 100% of the device-width):
var deviceWidth = 0;
$(window).bind('resize', function () {
deviceWidth = $('[data-role="page"]').first().width();
}).trigger('resize');
$(window).resize(function() {
var top_nav_height = $("#id_of_top_nav").height();
var bottom_nav_height = $("#id_of_bottom_nav").height();
var window_height = $(window).height();
var height_of_open_space = window_height - (top_nav_height+bottom_nav_height);
$("#id_of_img").css({
height:height_of_open_space+'px';
});
});
this will be fine with if 0px padding and margin, if not also get that values and subtract from height_of_open_space
before applying to img
height
It is a bit hard to tell without seeing any of your markup, but it should be feasable with pure css. I set up a very basic example to demonstrate: http://codepen.io/anon/pen/XbGJJO
HTML:
<div class='top'>
top navbar
</div>
<div class='content'>
<p> some content </p>
</div>
<div class='bottom'>
bottom navbar
</div>
CSS:
.top, .bottom {
height: 40px;
background: red;
position: fixed;
width: 100%;
}
.top {
top: 0;
}
.bottom {
bottom: 0;
}
.content {
margin: 40px 0;
min-height: calc(100vh - 80px);
background: green; /* background goes here */
}
The trick lies in the following line:
min-height: calc(100vh - 80px);
This tells your content to at least take up 100% of the vertical height, minus the height of the top and bottom bar. Let me know if you want me to explain further.
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