How can I change button color when it is clicked? I tried the :active style but it don't work on the android device (however it does work in the browser).
For example I have a button like this
<button class="button button-full button-calm button-login" type="submit">Sign In</button>
and styles like this
.login .button-login {
width:96%;
background: red;
margin: 0 auto;
border: 0;
border-radius: 4px;
moz-border-radius: 4px;
webkit-border-radius: 4px;
transition: all 0.3s ease 0s;
}
.login .button-login:active {
background: yellow;
}
I expect the button to become yellow when I touch it and become red back when the user lift the finger.
I think, nice idea will be to replace <button>
with a carefully styled <a>
.
For example like this.
#button { background-color: #E3E1B8; padding: 2px 4px; font: 13px sans-serif; text-decoration: none; border: 1px solid #000; border-color: #aaa #444 #444 #aaa; color: #000 } #button:hover { background-color: #46000D; }
<a href="#" id="button">New Element</a>
I have done it using Ionic Way what he has done in own css.
<button id="login2-button9" class="button button-gold">English</button>
Add this in your css file
.button.button-gold {
border-color: transparent;
background-color: #625031;
color: #000000; }
.button.button-gold:hover {
color: #000000;
text-decoration: none; }
.button.button-gold.active, .button.button-gold.activated {
background-color:#c0a062; }
.button.button-gold.button-clear {
border-color: transparent;
background: none;
box-shadow: none;
color: #625031; }
.button.button-gold.button-icon {
border-color: transparent;
background: none; }
.button.button-gold.button-outline {
border-color: #625031;
background: transparent;
color: #625031; }
.button.button-gold.button-outline.active, .button.button-gold.button-outline.activated {
background-color: #625031;
box-shadow: none;
color: #000000; }
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